Reasoning Aptitude > Data Interpretation
LINE GRAPH MCQs
Line Charts
Total Questions : 135
| Page 11 of 14 pages
Question 101. Directions (1 - 5): Study the following line graph carefully and answer the questions given below:
The number of students appearing for the Aptitude Test from Town E is approximately what percent of the total number of students appearing for the Aptitude Test from all the towns together?
The number of students appearing for the Aptitude Test from Town E is approximately what percent of the total number of students appearing for the Aptitude Test from all the towns together?
Answer: Option D. -> 21%
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{35\times1000}{167.5\times1000}\times100\right)\% \cr
& = \frac{350\times100}{1675}\% \cr
& = \frac{1400}{67}\% \cr
& = 20.89\% \cr
& \approx 21\% \cr} $$
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{35\times1000}{167.5\times1000}\times100\right)\% \cr
& = \frac{350\times100}{1675}\% \cr
& = \frac{1400}{67}\% \cr
& = 20.89\% \cr
& \approx 21\% \cr} $$
Answer: Option B. -> 13 : 16
Ratio of number of students from Town B to that from Town A
$$\eqalign{
& = \frac{32.5\times1000}{40\times1000} \cr
& = \frac{325}{400} \cr
& = \frac{13}{16} \cr
& = 13:16 \cr} $$
Ratio of number of students from Town B to that from Town A
$$\eqalign{
& = \frac{32.5\times1000}{40\times1000} \cr
& = \frac{325}{400} \cr
& = \frac{13}{16} \cr
& = 13:16 \cr} $$
Answer: Option A. -> 33500
Average number of students appearing in Aptitude Test from all towns
$$ = \frac{\left(40+32.5+17.5+42.5+35\right)\times1000}{5}$$
$$\eqalign{
& = \frac{167.5\times1000}{5} \cr
& = 33.5\times1000 \cr
& = 33500 \cr} $$
Average number of students appearing in Aptitude Test from all towns
$$ = \frac{\left(40+32.5+17.5+42.5+35\right)\times1000}{5}$$
$$\eqalign{
& = \frac{167.5\times1000}{5} \cr
& = 33.5\times1000 \cr
& = 33500 \cr} $$
Answer: Option A. -> 243%
$$\eqalign{
& \text{Required percentage} \cr
& = \left(\frac{42.5\times1000}{17.5\times1000}\times100\right)\% \cr
& = \left(\frac{425}{175}\times100\right)\% \cr
& = \frac{425\times4}{7}\% \cr
& = \frac{1700}{7}\% \cr
& = 242.85\% \cr
& \approx 243\% \cr} $$
$$\eqalign{
& \text{Required percentage} \cr
& = \left(\frac{42.5\times1000}{17.5\times1000}\times100\right)\% \cr
& = \left(\frac{425}{175}\times100\right)\% \cr
& = \frac{425\times4}{7}\% \cr
& = \frac{1700}{7}\% \cr
& = 242.85\% \cr
& \approx 243\% \cr} $$
Answer: Option A. -> Rs. 2.25 lakh
Let the investment of A in 2008 be Rs. $$x$$. Then,
$$\eqalign{
& \left(\frac{160}{100}\times x\right) = 24\text{ lakh} \cr
& \Rightarrow x = \left(24\times\frac{5}{8}\right) \text{lakh} \cr
& \Rightarrow x = 15 \text{ lakh} \cr} $$
∴ Investment of A in 2008 = 15 lakh
Profit of A in 2008
= Rs. (24 - 15) lakh
= Rs. 9 lakh
Investment of A in 2007
= Investment of A in 2008
= Rs. 15 lakh
Profit of A in 2007
$$\eqalign{
& =\text{Rs.} \left(\frac{45}{100}\times15\text{ lakh}\right) \cr
& =\text{Rs.} \frac{27}{4}\text{ lakh} \cr
& =\text{Rs. 6.75 lakh} \cr} $$
Difference between the profits of A in 2007 and 2008
= Rs. (9 - 6.75) lakh
= Rs. 2.25 lakh
Let the investment of A in 2008 be Rs. $$x$$. Then,
$$\eqalign{
& \left(\frac{160}{100}\times x\right) = 24\text{ lakh} \cr
& \Rightarrow x = \left(24\times\frac{5}{8}\right) \text{lakh} \cr
& \Rightarrow x = 15 \text{ lakh} \cr} $$
∴ Investment of A in 2008 = 15 lakh
Profit of A in 2008
= Rs. (24 - 15) lakh
= Rs. 9 lakh
Investment of A in 2007
= Investment of A in 2008
= Rs. 15 lakh
Profit of A in 2007
$$\eqalign{
& =\text{Rs.} \left(\frac{45}{100}\times15\text{ lakh}\right) \cr
& =\text{Rs.} \frac{27}{4}\text{ lakh} \cr
& =\text{Rs. 6.75 lakh} \cr} $$
Difference between the profits of A in 2007 and 2008
= Rs. (9 - 6.75) lakh
= Rs. 2.25 lakh
Answer: Option A. -> Rs. 13.8 lakh
Let the investment of A in 2006 be Rs. $$x$$
Then,
$$\eqalign{
& \text{Profit = 55% of Rs. }x \cr
& =\text{Rs.}\left(x\times\frac{55}{100}\right) \cr
& =\text{Rs.}\left(\frac{11x}{20}\right) \cr
& \therefore \frac{11x}{20} = 10.12\text{ lakh} \cr
& \Rightarrow \frac{11x}{20} = 10.12\times100000 \cr
& \Rightarrow \frac{11x}{20} = 1012000 \cr
& \Rightarrow x = 1012000\times\frac{20}{11} \cr
& \Rightarrow x = 1840000 \cr
& \Rightarrow x = \text{18.4 lakh} \cr} $$
$$\Rightarrow$$ Investment of A in 2006 = 18.4 lakh
Let the investment of A in 2006 be Rs. $$x$$
Then,
$$\eqalign{
& \text{Profit = 55% of Rs. }x \cr
& =\text{Rs.}\left(x\times\frac{55}{100}\right) \cr
& =\text{Rs.}\left(\frac{11x}{20}\right) \cr
& \therefore \frac{11x}{20} = 10.12\text{ lakh} \cr
& \Rightarrow \frac{11x}{20} = 10.12\times100000 \cr
& \Rightarrow \frac{11x}{20} = 1012000 \cr
& \Rightarrow x = 1012000\times\frac{20}{11} \cr
& \Rightarrow x = 1840000 \cr
& \Rightarrow x = \text{18.4 lakh} \cr} $$
$$\Rightarrow$$ Investment of A in 2006 = 18.4 lakh
Answer: Option D. -> Rs. 20 lakh
Average profit of A and B in 2010
$$\eqalign{
& = \frac{1}{2}\times\left[\left(\frac{90}{100}\times25\text{ lakh}\right)+\left(\frac{70}{100}\times25\text{ lakh}\right)\right] \cr
& = \frac{1}{2}\times\left(\frac{45}{2}+\frac{35}{2}\right)\text{lakh} \cr
& = \frac{80}{4}\text{ lakh} \cr
& = \text{20 lakh} \cr} $$
Average profit of A and B in 2010
$$\eqalign{
& = \frac{1}{2}\times\left[\left(\frac{90}{100}\times25\text{ lakh}\right)+\left(\frac{70}{100}\times25\text{ lakh}\right)\right] \cr
& = \frac{1}{2}\times\left(\frac{45}{2}+\frac{35}{2}\right)\text{lakh} \cr
& = \frac{80}{4}\text{ lakh} \cr
& = \text{20 lakh} \cr} $$
Answer: Option C. -> 34 : 31
Let the investment of each in 2005 be Rs. $$x$$
Then,
(Income of A) : (Income of B)
= Rs. ($$x$$ + 70% of $$x$$) : Rs. ($$x$$ + 55% of $$x$$) [∵ Income = (Investment) + (Profit)]
$$\eqalign{
& = \left(x+\frac{70x}{100}\right) : \left(x+\frac{55x}{100}\right)\cr
& = \left(x+\frac{7x}{10}\right) : \left(x+\frac{11x}{20}\right) \cr
& = \frac{17x}{10} : \frac{31x}{20} \cr
& = 34 : 31 \cr} $$
Let the investment of each in 2005 be Rs. $$x$$
Then,
(Income of A) : (Income of B)
= Rs. ($$x$$ + 70% of $$x$$) : Rs. ($$x$$ + 55% of $$x$$) [∵ Income = (Investment) + (Profit)]
$$\eqalign{
& = \left(x+\frac{70x}{100}\right) : \left(x+\frac{55x}{100}\right)\cr
& = \left(x+\frac{7x}{10}\right) : \left(x+\frac{11x}{20}\right) \cr
& = \frac{17x}{10} : \frac{31x}{20} \cr
& = 34 : 31 \cr} $$
Question 109. Directions (1 - 8): Study the following graphs carefully and answer the questions that follow:
If the total amount invested by the two companies in 2009 was Rs. 27 lakh, while the amount invested by Company B was 50% of the amount invested by Company A, what was the total profit earned by the two companies together?
If the total amount invested by the two companies in 2009 was Rs. 27 lakh, while the amount invested by Company B was 50% of the amount invested by Company A, what was the total profit earned by the two companies together?
Answer: Option B. -> Rs. 20.70 lakh
Let the investment of A in 2009 be Rs. $$x$$
Then,
Investment of B
$$\eqalign{
& = \text{50% of Rs. }x\cr
& =\text{Rs.} \left(x\times\frac{50}{100}\right) \cr
& =\text{Rs. } \frac{x}{2} \cr
& \therefore \left(x+\frac{x}{2}\right) = 27 \text{ lakh} \cr
& \Rightarrow \frac{3x}{2} = 27 \text{ lakh} \cr
& \Rightarrow x = \left(27\times\frac{2}{3}\right) \text{lakh} \cr
& \Rightarrow x = \text{18 lakh} \cr} $$
∴ Investment of A in 2009 = Rs. 18 lakh and investment of B = Rs. 9 lakh.
$$\eqalign{
& \text{Profit of A} \cr
& =\text{Rs.} \left(18\text{ lakh}\times \frac{75}{100}\right) \cr
& = \text{Rs. 13.50 lakh} \cr
& \text{Profit of B} \cr
& =\text{Rs.} \left(9\text{ lakh}\times \frac{80}{100}\right) \cr
& = \text{Rs. 7.20 lakh} \cr
& \therefore \text{Total profit of A and B} \cr
& = \text{Rs.}\left(13.50+7.20\right)\text{lakh} \cr
& = \text{Rs. 20.70 lakh} \cr} $$
Let the investment of A in 2009 be Rs. $$x$$
Then,
Investment of B
$$\eqalign{
& = \text{50% of Rs. }x\cr
& =\text{Rs.} \left(x\times\frac{50}{100}\right) \cr
& =\text{Rs. } \frac{x}{2} \cr
& \therefore \left(x+\frac{x}{2}\right) = 27 \text{ lakh} \cr
& \Rightarrow \frac{3x}{2} = 27 \text{ lakh} \cr
& \Rightarrow x = \left(27\times\frac{2}{3}\right) \text{lakh} \cr
& \Rightarrow x = \text{18 lakh} \cr} $$
∴ Investment of A in 2009 = Rs. 18 lakh and investment of B = Rs. 9 lakh.
$$\eqalign{
& \text{Profit of A} \cr
& =\text{Rs.} \left(18\text{ lakh}\times \frac{75}{100}\right) \cr
& = \text{Rs. 13.50 lakh} \cr
& \text{Profit of B} \cr
& =\text{Rs.} \left(9\text{ lakh}\times \frac{80}{100}\right) \cr
& = \text{Rs. 7.20 lakh} \cr
& \therefore \text{Total profit of A and B} \cr
& = \text{Rs.}\left(13.50+7.20\right)\text{lakh} \cr
& = \text{Rs. 20.70 lakh} \cr} $$
Answer: Option C. -> Rs. 10.23 lakh
$$\eqalign{
& \text{Investment of B in 2004 = 12 lakh} \cr
& \text{Income of B in 2004} \cr
& =\text{Rs.}\left(\frac{155}{100}\times12\text{ lakh}\right) \cr
& = \text{Rs. 18.6 lakh} \cr
& \text{Profit earned in 2005} \cr
& =\text{Rs.}\left(\frac{55}{100}\times18.6\text{ lakh}\right) \cr
& =\text{Rs.}\left(\frac{11}{10}\times9.3 \text{ lakh}\right) \cr
& =\text{Rs. 10.23 lakh} \cr} $$
$$\eqalign{
& \text{Investment of B in 2004 = 12 lakh} \cr
& \text{Income of B in 2004} \cr
& =\text{Rs.}\left(\frac{155}{100}\times12\text{ lakh}\right) \cr
& = \text{Rs. 18.6 lakh} \cr
& \text{Profit earned in 2005} \cr
& =\text{Rs.}\left(\frac{55}{100}\times18.6\text{ lakh}\right) \cr
& =\text{Rs.}\left(\frac{11}{10}\times9.3 \text{ lakh}\right) \cr
& =\text{Rs. 10.23 lakh} \cr} $$