Reasoning Aptitude > Data Interpretation
LINE GRAPH MCQs
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Total Questions : 135
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Answer: Option A. -> 34 : 23
Number of watches sold in Town X in the month of May = 180
Number of watches sold in Town X in the month of July
= $$\frac{180\times110}{100}$$
= 198
Number of watches sold in Town X in the month of January = 120
∴ Required ratio
$$\eqalign{
& = \frac{198}{120} \cr
& = \frac{33}{20} \cr
& = 33:20\cr} $$
Number of watches sold in Town X in the month of May = 180
Number of watches sold in Town X in the month of July
= $$\frac{180\times110}{100}$$
= 198
Number of watches sold in Town X in the month of January = 120
∴ Required ratio
$$\eqalign{
& = \frac{198}{120} \cr
& = \frac{33}{20} \cr
& = 33:20\cr} $$
Answer: Option B. -> 90
Total number of watches sold in both the towns together in the month of June
= 240 + 180
= 420
Total number of watches sold in both the towns together in March
= 180 + 150
= 330
Required difference
= 420 - 330
= 90
Total number of watches sold in both the towns together in the month of June
= 240 + 180
= 420
Total number of watches sold in both the towns together in March
= 180 + 150
= 330
Required difference
= 420 - 330
= 90
Answer: Option D. -> $$91\frac{2}{3}$$ %
Number of Watches sold in Town Y in February = 120
Number of Watches sold in Town Y in May = 230
Required percentage increase
$$\eqalign{
& = \frac{230-120}{120}\times100 \cr
& = \frac{110}{120}\times100 \cr
& = \frac{110\times5}{6}\cr
& = \frac{275}{3} \cr
& = 91\frac{2}{3}\% \cr} $$
Number of Watches sold in Town Y in February = 120
Number of Watches sold in Town Y in May = 230
Required percentage increase
$$\eqalign{
& = \frac{230-120}{120}\times100 \cr
& = \frac{110}{120}\times100 \cr
& = \frac{110\times5}{6}\cr
& = \frac{275}{3} \cr
& = 91\frac{2}{3}\% \cr} $$
Answer: Option D. -> 2
It is clear from the graph.
It is clear from the graph.
Answer: Option C. -> 25%
$$\eqalign{
& 2001 : \frac{\text{I}}{\text{E}} = \frac{1}{1} = \frac{4}{4} \cr
& 2002 : \frac{\text{I}}{\text{E}} = \frac{75}{100} = \frac{3}{4} \cr
& \text{Income} \% = \frac{4 - 3}{4} \times 100 = 25\% \cr}$$
$$\eqalign{
& 2001 : \frac{\text{I}}{\text{E}} = \frac{1}{1} = \frac{4}{4} \cr
& 2002 : \frac{\text{I}}{\text{E}} = \frac{75}{100} = \frac{3}{4} \cr
& \text{Income} \% = \frac{4 - 3}{4} \times 100 = 25\% \cr}$$
Answer: Option B. -> 400
The input into B is 1200 units and the output from B is (250 + 550) = 800 units.
Hence,
Demand = 1200 - 800 = 400 Units.
The input into B is 1200 units and the output from B is (250 + 550) = 800 units.
Hence,
Demand = 1200 - 800 = 400 Units.
Question 87. Directions (1 - 4): The following figure represents flow of natural gas through pipeline between major cities A, B, C, D and E (in suitable unit). Assume that supply equals demand. Refer to it and answer the following questions.-
If the total demand in E is 80% of demand in A, what is the demand in A?
If the total demand in E is 80% of demand in A, what is the demand in A?
Answer: Option A. -> 2500
The total demand in E = Total input into E.
→ 550 + 800 + 650 = 2000
$$\eqalign{
& = \frac{2000\times100}{80} \cr
& =2500 \cr} $$
Hence, the demand in A will be 2500.
The total demand in E = Total input into E.
→ 550 + 800 + 650 = 2000
$$\eqalign{
& = \frac{2000\times100}{80} \cr
& =2500 \cr} $$
Hence, the demand in A will be 2500.
Question 88. Directions (1 - 4): The following figure represents flow of natural gas through pipeline between major cities A, B, C, D and E (in suitable unit). Assume that supply equals demand. Refer to it and answer the following questions.-
Assuming the information of question number 2 and 3 to be true, what is the total demand in the five cities?
Assuming the information of question number 2 and 3 to be true, what is the total demand in the five cities?
Answer: Option B. -> 5775
Demand = A + B + C + D + E
= 2500 + 400 + 225 + 650 + 2000
= 5775
Demand = A + B + C + D + E
= 2500 + 400 + 225 + 650 + 2000
= 5775
Question 89. Directions (1 - 4): The following figure represents flow of natural gas through pipeline between major cities A, B, C, D and E (in suitable unit). Assume that supply equals demand. Refer to it and answer the following questions.-
If the number of units demanded in C is 225, what is the value of M?
If the number of units demanded in C is 225, what is the value of M?
Answer: Option A. -> 1075
C has a net output of 1100 units. If the demand is 225 at C, then to fulfill all conditions we need an input of 1325 into C. This will occur only if the value of M is 1075.
C has a net output of 1100 units. If the demand is 225 at C, then to fulfill all conditions we need an input of 1325 into C. This will occur only if the value of M is 1075.
Answer: Option D. -> 4 years
Clearly, Export > Import only when $$\frac{\text{Import}}{\text{Export}}$$ From the graph it is clear that the above ratio is less than 1 in the years 2005, 2006, 2007 and 2010.
Thus (Imports : Exports)
Clearly, Export > Import only when $$\frac{\text{Import}}{\text{Export}}$$ From the graph it is clear that the above ratio is less than 1 in the years 2005, 2006, 2007 and 2010.
Thus (Imports : Exports)