Answer: Option A. -> Rs. 1000000
Required difference,
= Rs. [(190 + 170) - (210 + 140)] lakh
= Rs. [360 - 350]
= Rs. 10 lakh
= Rs. 1000000

Answer: Option A. -> 75
$$\eqalign{
& \text{Required percentage} \cr
& = \frac{100+190+250}{80+100+130+200+210}\times100 \cr
& = 75\% \cr} $$

Answer: Option B. -> 2006
Total expenditure of 3 companies in 2005,
= (80 + 140 + 200)
= Rs. 420 lakh
Total expenditure of 3 companies in 2006,
= (100 + 190 + 250)
= Rs. 540 lakh
Total expenditure of 3 companies in 2007,
= Rs. 580 lakh
Total expenditure of 3 companies in 2008,
= Rs. 470 lakh
Total expenditure of 3 companies in 2009,
= Rs. 530 lakh
∴ The required answer is 2006.

Answer: Option B. -> Rs. 37.95 lakhs
Profit percent earned by company B in 2009 = 35%
Profit percent earned by company B in 2010 = 50%
Expenditure of company B in 2009 = 12 lakhs
Expenditure of company B in 2010 = 14.5 lakhs
Income of company B in 2009
$$\eqalign{
& 35\% = \frac{I - E}{E}\times100 \cr
& \Rightarrow 35 = \frac{I - 12\text{ lakh}}{12\text{ lakh}}\times100 \cr
& \Rightarrow \left(35\times12\right)\text{lakh} = 100I-1200\text{ lakh} \cr
& \Rightarrow 420\text{ lakh} = 100I - 1200 \text{ lakh} \cr
& \Rightarrow I = 16.20 \text{ lakh} \cr
& \text{Income of company B in 2009} \cr
& 50\% = \frac{I - E}{E}\times100 \cr
& \Rightarrow 50 = \frac{I - 14.5\text{ lakh}}{14.5\text{ lakh}}\times100 \cr
& \Rightarrow \left(50\times14.5\right)\text{lakh} = 100I-14.50\text{ lakh} \cr
& \Rightarrow 2175\text{ lakh} = 100I \text{ lakh} \cr
& \Rightarrow I = 21.75 \text{ lakh} \cr} $$
So,
Total income of company B in 2009 and 2010
= 16.2 + 21.75
= Rs. 37.95 lakhs

Answer: Option C. -> 29 : 45
$$\eqalign{
& \text{In 2010, 50} = \frac{2-E_1}{E_1}\times100 \cr
& \Rightarrow 50\,E_1= 200-100\,E_1 \cr
& \Rightarrow 150\,E_1 = 200 \cr
& \Rightarrow E_1 = \frac{4}{3} \cr
& \text{In 2011, 45} = \frac{3-E_2}{E_2}\times100 \cr
& \Rightarrow 45\,E_2 = 300 - 100\,E_2 \cr
& \Rightarrow 145\,E_2=300 \cr
& \Rightarrow E_2= \frac{300}{145} \cr
& \text{Then, }\frac{E_1}{E_2} = \frac{4}{3}\times\frac{145}{300} \cr
& \Rightarrow \frac{E_1}{E_2} = \frac{29}{45} \cr
& \Rightarrow E_1:E_2=29:45 \cr} $$

Answer: Option D. -> Cannot be determined
Solution cannot be determined because profit percentage of company A in all the years are not given.

Answer: Option A. -> 4 lakhs
Let the income of company A in 2013 = $$x$$
Let the income of company B in 2013 = (5.7 - $$x$$)
Expenditure of company A = Expenditure of company B
$$\eqalign{
& =E\, \frac{40}{100}-\frac{x-E}{E}\times100 \cr
& \frac{x}{E} = 1.4\,\, . . . . . \,\left(\text{i}\right) \text{ and} \cr
& \frac{45}{100} = \frac{\left(5.7-x\right)-E}{E} \cr
& \Rightarrow \frac{5.7-x}{E} = 14.5\,\, . . . . .\, \left(\text{ii}\right) \cr
& \text{Divide equation (ii) by (i) we get} \cr
& \Rightarrow \frac{5.7-x}{E}\times\frac{E}{x}=\frac{145}{140} \cr
& \Rightarrow \frac{5.7x}{x}=\frac{145}{140} \cr
& \Rightarrow 5.7\times140-140x=145x \cr
& \Rightarrow 798 = 285x \cr
& \Rightarrow x = 2.8 \text{ lakhs} \cr
& \because \frac{x}{E} = 1.4 \cr
& E = 2 \text{ lakhs} \cr
& \text{Total expenditure of two companies} \cr
& =2+2 \cr
& = 4 \text{ lakhs} \cr} $$

Answer: Option A. -> 21 : 26
$$\eqalign{
& \text{For company A, In 2012} \cr
& P\% = \frac{I-E}{E}\times100 \cr
& \Rightarrow 30 = \frac{I-3}{3}\times100 \cr
& \Rightarrow 90 = 100I-300\cr
& \Rightarrow \frac{390}{100} = I \cr
& \Rightarrow I = 3.9 \cr
& \text{For company B, In 2012} \cr
& P\% = \frac{I-E}{E}\times100 \cr
& \Rightarrow 40 = \frac{I-4}{4}\times100 \cr
& \Rightarrow 160 = 100I-400 \cr
& \Rightarrow \frac{560}{100} = I \cr
& \Rightarrow I = 5.6 \cr
& \text{Then required ratio} \cr
& = \frac{3.9}{5.6} \cr
& = \frac{39}{56} \cr
& = 39:56 \cr} $$

Answer: Option B. -> 40%
The number of watches sold in Town Y in April = 210
The number of watches sold in Town X in April = 150
Required percentage
$$\eqalign{
& = \frac{210-150}{150}\times100 \cr
& = \frac{60}{150}\times100 \cr
& =40\% \cr} $$

Answer: Option D. -> 170
Total number of watches sold in Town X in January, February, March and June
= 120 + 140 + 180 + 240
= 680
= Required average
= $$\frac{680}{4}$$
= 170