Reasoning Aptitude > Data Interpretation
LINE GRAPH MCQs
Line Charts
Total Questions : 135
| Page 10 of 14 pages
Question 91. Directions (1 - 5): The following line – graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 2005 to 2011.
If the imports in 2008 was Rs. 250 crores and the total exports in the years 2008 and 2009 together was Rs. 500 crores, then the imports in 2009 was-
If the imports in 2008 was Rs. 250 crores and the total exports in the years 2008 and 2009 together was Rs. 500 crores, then the imports in 2009 was-
Answer: Option D. -> Rs. 420 crores
Let the value of export in 2008 be Rs. $$x$$ crores
Then, the value of export in 2009 = Rs. (500 - $$x$$) crores
$$\eqalign{
& \frac{250}{x} = 1.25 \cr
& \Rightarrow x = \frac{250}{1.25} \cr
& \Rightarrow x = \frac{250\times100}{125} \cr
& \Rightarrow x = 200 \cr} $$
∴ Export in 2008 = Rs. 200 crores
Export in 2009
= Rs. (500 - 200) crores
= Rs. 300 crores
Let the value of import in 2009 be Rs. $$y$$ crores
Then,
$$\eqalign{
& \frac{y}{300} = 1.40 \cr
& \Rightarrow y = 1.40\times300 \cr
& \Rightarrow y = \frac{140}{100}\times300 \cr
& \Rightarrow y = 420 \cr} $$
Hence, the value of import in 2009 was Rs. 420 crores
Let the value of export in 2008 be Rs. $$x$$ crores
Then, the value of export in 2009 = Rs. (500 - $$x$$) crores
$$\eqalign{
& \frac{250}{x} = 1.25 \cr
& \Rightarrow x = \frac{250}{1.25} \cr
& \Rightarrow x = \frac{250\times100}{125} \cr
& \Rightarrow x = 200 \cr} $$
∴ Export in 2008 = Rs. 200 crores
Export in 2009
= Rs. (500 - 200) crores
= Rs. 300 crores
Let the value of import in 2009 be Rs. $$y$$ crores
Then,
$$\eqalign{
& \frac{y}{300} = 1.40 \cr
& \Rightarrow y = 1.40\times300 \cr
& \Rightarrow y = \frac{140}{100}\times300 \cr
& \Rightarrow y = 420 \cr} $$
Hence, the value of import in 2009 was Rs. 420 crores
Answer: Option D. -> Non of these
The graph gives only the ratio of value of imports and that of exports.
In order to find the percentage increase in imports from 2007 to 2008, we require the value of import or that of export during these years.
So, we cannot find the percentage increase in imports.
Hence, the data is inadequate to answer the question.
The graph gives only the ratio of value of imports and that of exports.
In order to find the percentage increase in imports from 2007 to 2008, we require the value of import or that of export during these years.
So, we cannot find the percentage increase in imports.
Hence, the data is inadequate to answer the question.
Answer: Option C. -> 2007
The imports are minimum proportionate to exports means (value of import) : (value of export) should have minimum value.
Clearly, this ratio has a minimum value of 0.35 in 2007
The imports are minimum proportionate to exports means (value of import) : (value of export) should have minimum value.
Clearly, this ratio has a minimum value of 0.35 in 2007
Answer: Option B. -> Rs. 320 crores
From graph, we find that the ratio of value of import to the value of export in 2006 is 0.85
Let the value of export in 2006 be Rs. $$x$$ crores.
Then,
$$\eqalign{
& \frac{272}{x} = 0.85 \cr
& \Rightarrow x = \frac{272}{0.85} \cr
& \Rightarrow x = \frac{272\times100}{85} \cr
& \Rightarrow x = 320 \cr} $$
Hence, the value of exports in 2006 was Rs. 320 crores
From graph, we find that the ratio of value of import to the value of export in 2006 is 0.85
Let the value of export in 2006 be Rs. $$x$$ crores.
Then,
$$\eqalign{
& \frac{272}{x} = 0.85 \cr
& \Rightarrow x = \frac{272}{0.85} \cr
& \Rightarrow x = \frac{272\times100}{85} \cr
& \Rightarrow x = 320 \cr} $$
Hence, the value of exports in 2006 was Rs. 320 crores
Answer: Option B. -> 60
(Trees planted by C in Tamil Nadu) - (Trees planted by A in Haryana)
= 160 - 80
= 80
(Trees planted by C in Tamil Nadu) - (Trees planted by A in Haryana)
= 160 - 80
= 80
Answer: Option B. -> 90%
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{100+60}{80+88}\times100\right)\% \cr
& = \left(\frac{160}{168}\times100\right)\% \cr
& = \frac{2000}{21}\% \cr
& \approx 95\% \cr} $$
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{100+60}{80+88}\times100\right)\% \cr
& = \left(\frac{160}{168}\times100\right)\% \cr
& = \frac{2000}{21}\% \cr
& \approx 95\% \cr} $$
Answer: Option B. -> 140
Average number of trees planted in Haryana by 3 NGOs
$$\eqalign{
& = \frac{1}{3}\left(80+140+167\right) \cr
& = \frac{387}{3} \cr
& = 129 \cr} $$
Average number of trees planted in Haryana by 3 NGOs
$$\eqalign{
& = \frac{1}{3}\left(80+140+167\right) \cr
& = \frac{387}{3} \cr
& = 129 \cr} $$
Answer: Option C. -> 6 : 4 : 5
Required ratio
= 180 : 120 : 150
= 6 : 4 : 5
Required ratio
= 180 : 120 : 150
= 6 : 4 : 5
Answer: Option B. -> Punjab
Total number of trees planted by A and B in:
Bihar → 100 + 60 = 160
Punjab → 120 + 80 = 200
Haryana → 140 + 80 = 220
Assam → 150 + 160 = 310
Tamil Nadu → 140 + 180 = 320
It is second lowest in Punjab
Total number of trees planted by A and B in:
Bihar → 100 + 60 = 160
Punjab → 120 + 80 = 200
Haryana → 140 + 80 = 220
Assam → 150 + 160 = 310
Tamil Nadu → 140 + 180 = 320
It is second lowest in Punjab
Question 100. Directions (1 - 5): Study the following line graph carefully and answer the questions given below:
What is the ratio of the number of students appearing for the Aptitude Test from Towns C and D together to the number of students appearing for the Aptitude Test from Towns A, D and E together?
What is the ratio of the number of students appearing for the Aptitude Test from Towns C and D together to the number of students appearing for the Aptitude Test from Towns A, D and E together?
Answer: Option B. -> 20 : 43
(Students from Towns C and D) : (Students from Towns A, D and E)
$$\eqalign{
& = \frac{\left(17.5+42.5\right)\times1000}{\left(40+42.5+35\right)\times1000} \cr
& = \frac{60}{117.5} \cr
& = \frac{600}{1175} \cr
& = \frac{24}{47} \cr
& = 24 : 47 \cr} $$
(Students from Towns C and D) : (Students from Towns A, D and E)
$$\eqalign{
& = \frac{\left(17.5+42.5\right)\times1000}{\left(40+42.5+35\right)\times1000} \cr
& = \frac{60}{117.5} \cr
& = \frac{600}{1175} \cr
& = \frac{24}{47} \cr
& = 24 : 47 \cr} $$
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