Answer: Option A. -> 48
(1/A)+(1/B) = (1/20) (1/B)+(1/C) = (1/30) (1/A)+(1/C) = (1/40) SOLVING THE THREE EQUATIONS,
A=48

Answer: Option C. -> 24 days
PART OF WORK DONE BY 1 MAN IN A DAY = 1/M PART OF WORK DONE BY 1 WOMAN IN A DAY
= 1/W (2/M)+(12/W) = (1/4) (4/M)+(6/W) = (1/5) SOLVING,
1/M = 1/40 ,1/W = 1/60 (1/M)+(1/W) = 5/120 = 1/24

Answer: Option C. -> 2/5
PART OF WORK COMPLETED BY BILAL IN A DAY = 1/15 PART OF WORK COMPLETED BY JALAL IN A DAY = 1/12 PART OF WORK COMPLETED BY THEM IN A DAY = (1/15)+(1/12) = 3/20 PART OF WORK COMPLETED BY THEM IN 4 DAYS = (3/20)*4 = 3/5 FRACTION OF WORK LEFT
= 1-(3/5)
= 2/5

Answer: Option C. -> 45 Rs.
ATIO OF TIME TAKEN BY A AND B= 10 : 15 = 2 : 3
RATIO OF WORK DONE IN THE SAME TIME = 3:2, SO, THE MONEY IS TO BE DIVIDED AMONG A AND B IN THE RATIO 3 : 2
A’S SHARE = RS. [75×3/5] = RS.45.

Answer: Option A. -> 120, 40, 60 days
LET A: BE THE TIME IN WHICH X & Y COMPLETES THEIR WORK = 30 DAYS
B: TIME IN WHICH Y & Z COMPLETES THEIR WORK = 24 DAYS
C: TIME IN WHICH X & Z COMPLETES THEIR WORK = 40 DAYS
X ALONE CAN COMPLETE THE WORK IN (2 * A * C) / (AB + BC – AC) DAYS
= 2 * 30 * 24 * 40 / ((30 * 24) + (24 * 40) – (30 * 40)) = 120 DAYS
Y ALONE CAN COMPLETE THE WORK IN 2 * A * B * C / (- AB + BC + AC) DAYS
= 2 * 30 * 24 * 40 / (-(30 * 24) + (24 * 40) + (30 * 40)) = 40 DAYS
Z ALONE CAN COMPLETE THE WORK IN 2 * A * B * C / (AB – BC + AC) DAYS
= 2 * 30 * 24 * 40 / ((30 * 24) – (24 * 40) + (30 * 40))
= 60 DAYS

Answer: Option D. -> Rs. 400
AMOUNT OF WORK A CAN DO IN 1 DAY = 1/6
AMOUNT OF WORK B CAN DO IN 1 DAY = 1/8
AMOUNT OF WORK A + B CAN DO IN 1 DAY = 1/6 + 1/8 = 7/24
AMOUNT OF WORK A + B + C CAN DO = 1/3
AMOUNT OF WORK C CAN DO IN 1 DAY = 1/3 – 7/24 = 1/24
WORK A CAN DO IN 1 DAY: WORK B CAN DO IN 1 DAY: WORK C CAN DO IN 1 DAY
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
AMOUNT TO BE PAID TO C = 3200 × (1/8) = 400

Answer: Option A. -> 5 5⁄11
A CAN COMPLETE THE WORK IN 12 DAYS WORKING 8 HOURS A DAY
=> NUMBER OF HOURS A CAN COMPLETE THE WORK = 12×8 = 96 HOURS
=> WORK DONE BY A IN 1 HOUR = 1/96
B CAN COMPLETE THE WORK IN 8 DAYS WORKING 10 HOURS A DAY
=> NUMBER OF HOURS B CAN COMPLETE THE WORK = 8×10 = 80 HOURS
=> WORK DONE BY B IN 1 HOUR = 1/80
WORK DONE BY A AND B IN 1 HOUR = 1/96 + 1/80 = 11/480
=> A AND B CAN COMPLETE THE WORK IN 480/11 HOURS
A AND B WORKS 8 HOURS A DAY
HENCE TOTAL DAYS TO COMPLETE THE WORK WITH A AND B WORKING TOGETHER
= (480/11)/ (8) = 60/11 DAYS = 5 5⁄11 DAYS

Answer: Option C. -> 15 hrs
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option C. -> 18
LET WORK DONE BY P IN 1 DAY = P,
WORK DONE BY Q IN 1 DAY = Q,
WORK DONE BY R IN 1 DAY = R
P + Q = 1/30
Q + R = 1/24
R + P = 1/20
ADDING ALL THE ABOVE, 2P + 2Q + 2R = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> P + Q + R = 1/16
=> WORK DONE BY P,Q AND R IN 1 DAY = 1/16
WORK DONE BY P, Q AND R IN 10 DAYS = 10 × (1/16) = 10/16 = 5/8
REMAINING WORK = 1 = 5/8 = 3/8
WORK DONE BY P IN 1 DAY = WORK DONE BY P,Q AND R IN 1 DAY – WORK DONE BY Q AND R IN 1 DAY
= 1/16 – 1/24 = 1/48
NUMBER OF DAYS P NEEDS TO WORK TO COMPLETE THE REMAINING WORK = (3/8) / (1/48) = 18

Answer: Option A. -> 7.5 hrs
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!