Quantitative Aptitude
TIME AND WORK MCQs
Time & Work, Work And Wages
Total Questions : 1512
| Page 151 of 152 pages
Answer: Option A. -> 32 hours
PART OF TASK COMPLETED BY A IN A DAY = 1/X PART OF TASK COMPLETED BY B IN A DAY = 3/X (B IS THRICE AS EFFICIENT AS A) (1/X)+(3/X) = 1 4/X = 1 X = 4 B COMPLETES 3/4TH OF THE TASK IN A DAY. HE TAKES 4/3 DAYS TO COMPLETE THE ENTIRE TASK. 4/3 DAYS = (4/3*24) HOURS = 32 HOURS
PART OF TASK COMPLETED BY A IN A DAY = 1/X PART OF TASK COMPLETED BY B IN A DAY = 3/X (B IS THRICE AS EFFICIENT AS A) (1/X)+(3/X) = 1 4/X = 1 X = 4 B COMPLETES 3/4TH OF THE TASK IN A DAY. HE TAKES 4/3 DAYS TO COMPLETE THE ENTIRE TASK. 4/3 DAYS = (4/3*24) HOURS = 32 HOURS
Answer: Option B. -> 41/4 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option B. -> 10 days
(4/M)+(2/W) = 1/2 2/M = 1/5 1/M = 1/10 (4/10)+(2/W) = (1/2) 2/W = 1/10 2 WOMEN ALONE TAKE 10 DAYS.
(4/M)+(2/W) = 1/2 2/M = 1/5 1/M = 1/10 (4/10)+(2/W) = (1/2) 2/W = 1/10 2 WOMEN ALONE TAKE 10 DAYS.
Answer: Option C. -> 5(1/3) days
(1/A)+(1/B) = (1/6) (1/B)+(1/C) = (1/12) (1/A)+(1/C) = (1/8) SOLVING THE THREE EQUATIONS,
(1/A)+(1/B)+(1/C) = (3/16) TOGETHER THEY TAKE 16/3 = 5(1/3) DAYS TO COMPLETE THE TASK.
(1/A)+(1/B) = (1/6) (1/B)+(1/C) = (1/12) (1/A)+(1/C) = (1/8) SOLVING THE THREE EQUATIONS,
(1/A)+(1/B)+(1/C) = (3/16) TOGETHER THEY TAKE 16/3 = 5(1/3) DAYS TO COMPLETE THE TASK.
Answer: Option C. -> 16 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 8 days
(A + B + C)’S 1 DAY’S WORK = 1/6; (A + B)’S 1 DAY’S WORK = 1/8 (B + C)’S 1 DAY’S WORK = 1/12 (A + C)’S 1 DAY’S WORK = ( 2 X 1/6 ) – ( 1/8 + 1/12 ) = ( 1/3 – 5/24 ) = 3/24 = 1/8 SO, A AND C TOGETHER WILL DO THE WOIRK IN 8 DAYS.
(A + B + C)’S 1 DAY’S WORK = 1/6; (A + B)’S 1 DAY’S WORK = 1/8 (B + C)’S 1 DAY’S WORK = 1/12 (A + C)’S 1 DAY’S WORK = ( 2 X 1/6 ) – ( 1/8 + 1/12 ) = ( 1/3 – 5/24 ) = 3/24 = 1/8 SO, A AND C TOGETHER WILL DO THE WOIRK IN 8 DAYS.
Answer: Option C. -> 25 days
(A + B)’S 1 DAY’S WORK = 1/10; C’S 1 DAY’S WORK = 1/50 (A + B + C)’S 1 DAY’S WORK = 1/10 + 1/50 = 6/50 = 3/25 ALSO, A’S 1 DAY’S WORK = (B + C)’S 1 DAY’S WORK
FROM (I) AND (II), WE GET : 2 X (A’S 1 DAY’S WORK) = 3/25 AS 1 DAY’S WORK = 3/50 B’S 1 DAY’S WORK = 1/10 – 3/50 = 2/50 = 1/25 SO, B ALONE COULD DO THE WORK IN 25 DAYS.
(A + B)’S 1 DAY’S WORK = 1/10; C’S 1 DAY’S WORK = 1/50 (A + B + C)’S 1 DAY’S WORK = 1/10 + 1/50 = 6/50 = 3/25 ALSO, A’S 1 DAY’S WORK = (B + C)’S 1 DAY’S WORK
FROM (I) AND (II), WE GET : 2 X (A’S 1 DAY’S WORK) = 3/25 AS 1 DAY’S WORK = 3/50 B’S 1 DAY’S WORK = 1/10 – 3/50 = 2/50 = 1/25 SO, B ALONE COULD DO THE WORK IN 25 DAYS.
Answer: Option C. -> 12 days
(A.+ B)’S 1 DAY’S WORK = ( 1/15 + 1/10 ) = 1/6 WORK DONE BY A AND B IN 2 DAYS = ( 1/6 X 2 ) = 1/3 REMAINING WORK = ( 1 – 1/6 ) = 2/3
NOW, 1/15 WORK IS DONE BY A IN 1 DAY. SO 2/3 WORK WILL BE DONE BY A IN ( 15 X 2/3 ) = 10 DAYS HENCE, TOTAL TIME TAKEN = (10 + 2) = 12 DAYS.
(A.+ B)’S 1 DAY’S WORK = ( 1/15 + 1/10 ) = 1/6 WORK DONE BY A AND B IN 2 DAYS = ( 1/6 X 2 ) = 1/3 REMAINING WORK = ( 1 – 1/6 ) = 2/3
NOW, 1/15 WORK IS DONE BY A IN 1 DAY. SO 2/3 WORK WILL BE DONE BY A IN ( 15 X 2/3 ) = 10 DAYS HENCE, TOTAL TIME TAKEN = (10 + 2) = 12 DAYS.
Answer: Option B. -> 4 : 3
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 15 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!