Quantitative Aptitude
TIME AND WORK MCQs
Time & Work, Work And Wages
Total Questions : 1512
| Page 146 of 152 pages
Answer: Option D. -> 136 days
TIME TAKEN IS INVERSELY PROPORTIONAL TO THEIR EFFICIENCY. SO, TIME TAKEN IS IN THE RATIO 8:5. TIME TAKEN BY RASHID TO FINISH THE WORK = 8X TIME TAKEN BY DANISH TO FINISH THE WORK = 5X 8X-5X=51 3X=51 X=17 8X=136
TIME TAKEN IS INVERSELY PROPORTIONAL TO THEIR EFFICIENCY. SO, TIME TAKEN IS IN THE RATIO 8:5. TIME TAKEN BY RASHID TO FINISH THE WORK = 8X TIME TAKEN BY DANISH TO FINISH THE WORK = 5X 8X-5X=51 3X=51 X=17 8X=136
Question 1452. Mansoor-Ul-Haque and Aaqib are working on a special assignment. Mansoor-Ul-Haque needs 6 hours to type 32 pages on a computer and Aaqib needs 5 hours to type 40 pages. If both of them work together on two different computers, how much time is needed to type an assignment of 110 pages?
Answer: Option C. -> 8 hour 15 minutes
PAGES TYPED BY MANSOOR-UL-HAQUE IN 1 HOUR = 32/6 = 16/3
PAGES TYPED BY AAQIB IN 1 HOUR = 40/5 = 8
PAGES TYPED BY MANSOOR-UL-HAQUE AND AAQIB IN 1 HOUR = 16/3 + 8 = 40/3
TIME TAKEN TO TYPE 110 PAGES WHEN MANSOOR-UL-HAQUE AND AAQIB WORK TOGETHER = 110 × 3 /40 = 33/4
= 8 ¼ HOURS = 8 HOUR 15 MINUTES
PAGES TYPED BY MANSOOR-UL-HAQUE IN 1 HOUR = 32/6 = 16/3
PAGES TYPED BY AAQIB IN 1 HOUR = 40/5 = 8
PAGES TYPED BY MANSOOR-UL-HAQUE AND AAQIB IN 1 HOUR = 16/3 + 8 = 40/3
TIME TAKEN TO TYPE 110 PAGES WHEN MANSOOR-UL-HAQUE AND AAQIB WORK TOGETHER = 110 × 3 /40 = 33/4
= 8 ¼ HOURS = 8 HOUR 15 MINUTES
Answer: Option C. -> 16
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option A. -> 16
12 MEN WORK 8 HOURS FOR 10 DAYS X MEN WORK 12 HOURS FOR 5 DAYS X = (12*8*10)/(12*5) = 16 MEN
12 MEN WORK 8 HOURS FOR 10 DAYS X MEN WORK 12 HOURS FOR 5 DAYS X = (12*8*10)/(12*5) = 16 MEN
Question 1455. Machine P can print one lakh books in 8 hours. Machine Q can print the same number of books in 10 hours while machine R can print the same in 12 hours. All the machines started printing at 9 A.M. Machine P is stopped at 11 A.M. and the remaining two machines complete work. Approximately at what time will the printing of one lakh books be completed?
Answer: Option C. -> 1:00 pm
WORK DONE BY P IN 1 HOUR = 1/8
WORK DONE BY Q IN 1 HOUR = 1/10
WORK DONE BY R IN 1 HOUR = 1/12
WORK DONE BY P,Q AND R IN 1 HOUR = 1/8 + 1/10 + 1/12 = 37/120
WORK DONE BY Q AND R IN 1 HOUR = 1/10 + 1/12 = 22/120 = 11/60
FROM 9 AM TO 11 AM, ALL THE MACHINES WERE OPERATING.
IE, THEY ALL OPERATED FOR 2 HOURS AND WORK COMPLETED = 2 × (37/120) = 37/60
PENDING WORK = 1- 37/60 = 23/60
HOURS TAKEN BY Q AN R TO COMPLETE THE PENDING WORK = (23/60) / (11/60) = 23/11
WHICH IS APPROXIMATELY EQUAL TO 2
HENCE THE WORK WILL BE COMPLETED APPROXIMATELY 2 HOURS AFTER 11 AM ; IE AROUND 1 PM
WORK DONE BY P IN 1 HOUR = 1/8
WORK DONE BY Q IN 1 HOUR = 1/10
WORK DONE BY R IN 1 HOUR = 1/12
WORK DONE BY P,Q AND R IN 1 HOUR = 1/8 + 1/10 + 1/12 = 37/120
WORK DONE BY Q AND R IN 1 HOUR = 1/10 + 1/12 = 22/120 = 11/60
FROM 9 AM TO 11 AM, ALL THE MACHINES WERE OPERATING.
IE, THEY ALL OPERATED FOR 2 HOURS AND WORK COMPLETED = 2 × (37/120) = 37/60
PENDING WORK = 1- 37/60 = 23/60
HOURS TAKEN BY Q AN R TO COMPLETE THE PENDING WORK = (23/60) / (11/60) = 23/11
WHICH IS APPROXIMATELY EQUAL TO 2
HENCE THE WORK WILL BE COMPLETED APPROXIMATELY 2 HOURS AFTER 11 AM ; IE AROUND 1 PM
Answer: Option A. -> 8/15
AMOUNT OF WORK P CAN DO IN 1 DAY = 1/15
AMOUNT OF WORK Q CAN DO IN 1 DAY = 1/20
AMOUNT OF WORK P AND Q CAN DO IN 1 DAY = 1/15 + 1/20 = 7/60
AMOUNT OF WORK P AND Q CAN TOGETHER DO IN 4 DAYS = 4 × (7/60) = 7/15
FRACTION OF WORK LEFT = 1 – 7/15= 8/15
AMOUNT OF WORK P CAN DO IN 1 DAY = 1/15
AMOUNT OF WORK Q CAN DO IN 1 DAY = 1/20
AMOUNT OF WORK P AND Q CAN DO IN 1 DAY = 1/15 + 1/20 = 7/60
AMOUNT OF WORK P AND Q CAN TOGETHER DO IN 4 DAYS = 4 × (7/60) = 7/15
FRACTION OF WORK LEFT = 1 – 7/15= 8/15
Answer: Option C. -> 12:00 am
JAMEEL WORKS FOR 5 HOURS. SO HE COMPLETES 5/15 = 1/3 OF THE TASK NASIR HAS TO COMPLETE 2/3RD OF THE TASK 12*2/3 = 8 HOURS ARE NEEDED. HE COMPLETES THE TASK AT 12:00 AM.
JAMEEL WORKS FOR 5 HOURS. SO HE COMPLETES 5/15 = 1/3 OF THE TASK NASIR HAS TO COMPLETE 2/3RD OF THE TASK 12*2/3 = 8 HOURS ARE NEEDED. HE COMPLETES THE TASK AT 12:00 AM.
Answer: Option A. -> 10
WORK DONE BY P IN 1 DAY = 1/24
WORK DONE BY Q IN 1 DAY = 1/9
WORK DONE BY R IN 1 DAY = 1/12
WORK DONE BY Q AND R IN 1 DAY = 1/9 + 1/12 = 7/36
WORK DONE BY Q AND R IN 3 DAYS = 3×7/36 = 7/12
REMAINING WORK = 1 – 7/12 = 5/12
NUMBER OF DAYS IN WHICH P CAN FINISH THE REMAINING WORK = (5/12) / (1/24) = 10
WORK DONE BY P IN 1 DAY = 1/24
WORK DONE BY Q IN 1 DAY = 1/9
WORK DONE BY R IN 1 DAY = 1/12
WORK DONE BY Q AND R IN 1 DAY = 1/9 + 1/12 = 7/36
WORK DONE BY Q AND R IN 3 DAYS = 3×7/36 = 7/12
REMAINING WORK = 1 – 7/12 = 5/12
NUMBER OF DAYS IN WHICH P CAN FINISH THE REMAINING WORK = (5/12) / (1/24) = 10
Answer: Option A. -> 50
PART OF WORK COMPLETED BY FARJAN AND KASHIF IN A DAY
= 1/30 PART OF WORK COMPLETED BY THEM IN 20 DAYS
= 20/30 = 2/3 1/3 OF THE WORK IS REMAINING. KASHIF COMPLETES 1/3RD OF THE WORK IN 25 DAYS. PART OF WORK COMPLETED BY HIM IN A DAY
= (1/3)÷25
= 1/75 (1/D)+(1/V) = 1/30 (1/D) = (1/30)-(1/75) = 1/50 FARJAN CAN COMPLETE IT IN 50 DAYS.
PART OF WORK COMPLETED BY FARJAN AND KASHIF IN A DAY
= 1/30 PART OF WORK COMPLETED BY THEM IN 20 DAYS
= 20/30 = 2/3 1/3 OF THE WORK IS REMAINING. KASHIF COMPLETES 1/3RD OF THE WORK IN 25 DAYS. PART OF WORK COMPLETED BY HIM IN A DAY
= (1/3)÷25
= 1/75 (1/D)+(1/V) = 1/30 (1/D) = (1/30)-(1/75) = 1/50 FARJAN CAN COMPLETE IT IN 50 DAYS.
Answer: Option B. -> 16
WORK DONE BY KAMAL IN 1 DAY = 1/20
WORK DONE BY SURESH IN 1 DAY = (1/20) × (125/100) = 5/80 = 1/16
=> SURESH CAN COMPLETE THE WORK IN 16 DAYS
WORK DONE BY KAMAL IN 1 DAY = 1/20
WORK DONE BY SURESH IN 1 DAY = (1/20) × (125/100) = 5/80 = 1/16
=> SURESH CAN COMPLETE THE WORK IN 16 DAYS
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