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Quantitative Aptitude

TIME AND WORK MCQs

Time & Work, Work And Wages

Total Questions : 1512 | Page 2 of 152 pages
Question 11.

  1. A takes twice as long as B and C together take to do a piece of work and B takes twice as long as A and C together. However, the 3 men together can complete the work in 30 days. How long would C alone take to do the work?

  1.    63 days
  2.    72 days
  3.    81 days
  4.    90 days
 Discuss Question
Answer: Option D. -> 90 days
Question 12.

  1. A can do half of a piece of work in one day whereas B can do full. B can do half the work as C in one day. Ratio of their efficiencies is

  1.    1 : 2 : 4
  2.    2 : 1 : 4
  3.    2 : 4 : 1
  4.    4 : 2 :1
 Discuss Question
Answer: Option A. -> 1 : 2 : 4
Question 13.

  1. Two men and three women working 7 hours a day finish a piece of work in 5 days. Four men and four women working 3 hours a day complete the same work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is

  1.    4 days 
  2.    5 days
  3.    6 days
  4.    7 days
 Discuss Question
Answer: Option B. -> 5 days
Question 14.

  1. A is twice as good a workman as B and they together took 7 days to do a piece of work. B alone can do it in

  1.    18 days
  2.    21 days
  3.    24 days
  4.     none of these
 Discuss Question
Answer: Option B. -> 21 days
Question 15.

  1. A can do a piece of work in 40 days. B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in

  1.    24  days
  2.    28 days
  3.    32 days
  4.    34 days
 Discuss Question
Answer: Option A. -> 24  days
Question 16.

  1. If 5 men or 9 boys can do a piece of work in 15 days then 10 men and 12 boys can finish the same work in

  1.    4 days
  2.    \(4\frac{1}{2}\)
  3.    5
  4.    \(5\frac{1}{2}\)
 Discuss Question
Answer: Option B. -> \(4\frac{1}{2}\)
Question 17.

  1. Some persons can do a piece of work in 12 days. Two times the number of these persons will do half of that work in

  1.    2 days
  2.    3 days
  3.    4 days
  4.    5 days
 Discuss Question
Answer: Option B. -> 3 days
Question 18.
  1. Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days, Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning till end. In how many days was the whole work done?

  1.    15 days
  2.    16 days
  3.    17 days
  4.    18 days
 Discuss Question
Answer: Option B. -> 16 days
The given problem is based on the concept of Work and Time.
Work is defined as the amount of effort put in by a person to complete a given task.
Time is the measure of duration or the interval between two events.
The formula for calculating the work done by three persons working together is
Total Work = 1/ (1/A + 1/B + 1/C)
Here, A, B and C represents the time taken by each of the three persons to complete the given task.
In the given problem, A = 18 days, B = 27 days and C= 36 days.
Therefore, applying the formula,
Total Work = 1/ (1/18 + 1/27 + 1/36)
Total Work = 16 days
Thus, the whole work was completed in 16 days.
Question 19.
  1. Father is two times faster than his son. If father and son can complete a job in 12 days how long will it take for the son alone to complete the same job?

  1.    12 days
  2.    24 days
  3.    36 days
  4.    none of these
 Discuss Question
Answer: Option C. -> 36 days
Let's assume that the son's speed is x units per day.Then, the father's speed is twice as fast, which means his speed is 2x units per day.
Now, let's consider the job that needs to be completed. Let the total work be W.The time taken by the father to complete the job alone can be calculated using the formula:
time taken = work / rate
where rate is the speed at which the job is done.
So, the father's time taken to complete the job alone is:
W / (2x)
Similarly, the time taken by the son to complete the job alone is:
W / x
Now, let's consider the time taken by the father and son together to complete the job.We know that they can complete the job in 12 days.Using the formula:
work done = rate * time taken
we can write:
W = (2x + x) * 12
Simplifying this equation, we get:
W = 36x
Now, we can substitute the value of W in the above equations to find the time taken by the father and son to complete the job alone.
Time taken by the father alone:
W / (2x) = (36x) / (2x) = 18 days
Time taken by the son alone:
W / x = 36 days
Therefore, the correct answer is option C, 36 days.
To summarize:
  • Let x be the son's speed and 2x be the father's speed.
  • Let W be the total work that needs to be done.
  • Father's time taken to complete the job alone: W / (2x)
  • Son's time taken to complete the job alone: W / x
  • Using W = 36x, we get father's time taken = 18 days and son's time taken = 36 days.
If you think the solution is wrong then please provide your own solution below in the comments section .
Question 20.

  1. 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same if 3 women do as much work as 2 men?

  1.    20 
  2.    30
  3.    40
  4.    none of these
 Discuss Question
Answer: Option B. -> 30

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