Answer: Option B. -> 5:3
X ———— Y ———— Z
IF ‘D’ IS THE DISTANCE BETWEEN X AND Y, THEN ‘D’ IS THE DISTANCE BETWEEN Y AND Z.
NOW THE TOTAL TIME FOR THE BATSMAN TO ROW FROM X TO Z IS 4 HOURS. THEREFORE, TIME TO ROW FROM X TO Y IS 2 HOURS.
ALSO THE TIME FOR THE BOATS MAN TO ROW FROM X TO Y AND BACK IS 10 HOURS. HENCE, TIME REQUIRED TO ROW FROM Y TO X IS 8 HOURS.
IF, A: SPEED OF BOATS MAN IN STILL WATER
B: SPEED OF THE RIVER
D/(A + B) = 2; D/(A – B) = 8
2*(A + B) = 8*(A – B)
A + B = 4A – 4B
3A = 5B
A:B = 5:3

Answer: Option C. -> 44
LET THE SPEED OF THE FASTER TRAIN BE X MILES PER HOUR AND
THE DISTANCE TRAVELLED BY IT WHEN IT MEETS THE SLOWER TRAIN BE Y MILES. TIME TAKEN BY THE FASTER TRAIN TO COVER Y MILES
= TIME TAKEN BY THE SLOWER TRAIN TO COVER (287-Y) MILES
= 3.5 HOURS (Y/X) = (287-Y)/(X-6) = 3.5 SOLVING, X = 44 MILES/HR

Answer: Option C. -> 40 minutes
LET HIS
USUAL SPEED BE X KMPH
USUAL TRAVEL TIME BE T HOURS
DISTANCE TO OFFICE BE D KM D=XT D=(0.8X)*[T+(10/60)] XT=0.8XT+(2X/15) SOLVING,
T=40 MINUTES

Answer: Option C. -> 71.11 km/hr
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option D. -> 32 minutes
(2/3)*24=16 MILES TIME TAKEN TO COVER THE FIRST 16 MILES
= (16/40) HOURS
= 24 MINUTES TIME TAKEN TO COVER THE NEXT 8 MILES
= (8/60) HOURS
= 8 MINUTES TIME TAKEN FOR THE ENTIRE JOURNEY
= 32 MINUTES

Answer: Option B. -> 4.8 kmph
TIME TAKEN FOR THE FORWARD JOURNEY
= 2/6 = (1/3) HRS TIME TAKEN FOR THE RETURN JOURNEY
= 2/4 = (1/2) HRS TOTAL TIME = 5/6 HRS AVERAGE SPEED = 4/(5/6) = 24/5 = 4.8KMPH

Answer: Option C. -> 7 hrs 45 min
GIVEN THAT TIME TAKEN FOR RIDING BOTH WAYS WILL BE 2 HOURS LESSER THAN
THE TIME NEEDED FOR WAKING ONE WAY AND RIDING BACK
FROM THIS, WE CAN UNDERSTAND THAT
TIME NEEDED FOR RIDING ONE WAY = TIME NEEDED FOR WAKING ONE WAY – 2 HOURS
GIVEN THAT TIME TAKEN IN WALKING ONE WAY AND RIDING BACK = 5 HOURS 45 MIN
HENCE THE TIME HE WOULD TAKE TO WALK BOTH WAYS = 5 HOURS 45 MIN + 2 HOURS = 7 HOURS 45 MIN

Answer: Option C. -> 3.6 km/hr
LET X BE THE SPEED OF THE RIVER.
DS = (6 + X) KM/HR; US = (6 – X) KM/HR
IF T HOURS IS THE TIME TO ROW DOWNSTREAM THEN 4T HOURS IS THE TIME TO ROW UPSTREAM.
(6 + X)*T = (6 – X)*4T
6 + X = 24 – 4X
X = 3.6 KM/HR

Answer: Option D. -> 1:1
RAYAN’S SPEED = 1000/300 = 3.33 M/S
HENCE RATIO = 1:1

Answer: Option C. -> 0.78 minutes
TOTAL DISTANCE = ADDITION OF LENGTH OF THE TWO TRAINS = 140 + 120 = 260 METRES
AS THE TWO TRAINS ARE TRAVELLING IN THE SAME DIRECTION, THEIR RELATIVE SPEED IS:
V = | V1 – V2 | = | 40 – 60 | = 20 KM/HR = 20*1000/60 = 1000/3 METRES/MIN
T = 260/ 1000*3
T = 0.78 MINUTES