Question
At 10 a.m. two trains started traveling toward each other from stations 287 miles apart. They passed each other at 1:30 p.m. the same day. If the average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour, which of the following represents the speed of the faster train, in miles per hour?
Answer: Option C
LET THE SPEED OF THE FASTER TRAIN BE X MILES PER HOUR AND
THE DISTANCE TRAVELLED BY IT WHEN IT MEETS THE SLOWER TRAIN BE Y MILES. TIME TAKEN BY THE FASTER TRAIN TO COVER Y MILES
= TIME TAKEN BY THE SLOWER TRAIN TO COVER (287-Y) MILES
= 3.5 HOURS (Y/X) = (287-Y)/(X-6) = 3.5 SOLVING, X = 44 MILES/HR
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LET THE SPEED OF THE FASTER TRAIN BE X MILES PER HOUR AND
THE DISTANCE TRAVELLED BY IT WHEN IT MEETS THE SLOWER TRAIN BE Y MILES. TIME TAKEN BY THE FASTER TRAIN TO COVER Y MILES
= TIME TAKEN BY THE SLOWER TRAIN TO COVER (287-Y) MILES
= 3.5 HOURS (Y/X) = (287-Y)/(X-6) = 3.5 SOLVING, X = 44 MILES/HR
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