Quantitative Aptitude
SPEED TIME AND DISTANCE MCQs
Time And Distance, Time & Distance, Speed Time & Distance
Total Questions : 1223
| Page 121 of 123 pages
Answer: Option B. -> 4 kmph
IF HE TRAVELS AT 6 KMPH,
TIME TAKEN TO REACH = 12/6 = 2 HOURS BUT HE TAKES 3 HOURS.
SPEED = 12/3 = 4 KMPH
IF HE TRAVELS AT 6 KMPH,
TIME TAKEN TO REACH = 12/6 = 2 HOURS BUT HE TAKES 3 HOURS.
SPEED = 12/3 = 4 KMPH
Answer: Option C. -> 120 kmph
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option D. -> 40
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 3750m
AVERAGE SPEED FOR RAJ IS: V = (2*9*10)/(9+10) = 180/19 KM/HR = 50/19 M/S
AVERAGE SPEED FOR ROHIT = 12 KM/HR = 10/3 M/S
NOW, V = D/T
AS D IS SAME, V*T = CONSTANT.
LET, T BE THE TIME TAKEN BY ROHIT IN SECONDS. HENCE, TIME TAKEN BY RAJ IS (T +600)S
50/19 * (T + 600) = 10/3 * T
150*(T + 600) = 190T
T = 2250S
LET D BE THE DISTANCE BETWEEN THE HOUSE AND THE OFFICE
2D = 2250 * 10/3
2D = 7500 M
D = 3750M
AVERAGE SPEED FOR RAJ IS: V = (2*9*10)/(9+10) = 180/19 KM/HR = 50/19 M/S
AVERAGE SPEED FOR ROHIT = 12 KM/HR = 10/3 M/S
NOW, V = D/T
AS D IS SAME, V*T = CONSTANT.
LET, T BE THE TIME TAKEN BY ROHIT IN SECONDS. HENCE, TIME TAKEN BY RAJ IS (T +600)S
50/19 * (T + 600) = 10/3 * T
150*(T + 600) = 190T
T = 2250S
LET D BE THE DISTANCE BETWEEN THE HOUSE AND THE OFFICE
2D = 2250 * 10/3
2D = 7500 M
D = 3750M
Answer: Option B. -> 45 km
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option D. -> 720 km/hr
DISTANCE = SPEED X TIME = 240 X 5 KM
NEW TIME =5/3 HR
HENCE, NEW SPEED = DISTANCE/TIME =240*5/5/3
=240×3=720 KM/HR
DISTANCE = SPEED X TIME = 240 X 5 KM
NEW TIME =5/3 HR
HENCE, NEW SPEED = DISTANCE/TIME =240*5/5/3
=240×3=720 KM/HR
Answer: Option A. -> 216 km
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 80 km
LET THE SPEED OF THE BIKE BE X KMPH. THEN THE SPEED OF THE CAR WILL BE 3X/2 KMPH. TIME TAKEN BY THE BIKE
T1 = 100/X TIME TAKEN BY THE BIKE
T2 = 100/(3X/2) T1 – T2 = 25/60 (100/X) – (100/(3X/2)) = 5/12 SOLVING THE EQUATION, X = 80 KMPH
LET THE SPEED OF THE BIKE BE X KMPH. THEN THE SPEED OF THE CAR WILL BE 3X/2 KMPH. TIME TAKEN BY THE BIKE
T1 = 100/X TIME TAKEN BY THE BIKE
T2 = 100/(3X/2) T1 – T2 = 25/60 (100/X) – (100/(3X/2)) = 5/12 SOLVING THE EQUATION, X = 80 KMPH
Answer: Option B. -> 35 km/hr
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option D. -> 10.8 kmph
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!