Question
A man travels a distance of 2 km by walking at a speed of 6 km/hr. He returns back at a speed of 4 km/hr. What is his average speed?
Answer: Option B
TIME TAKEN FOR THE FORWARD JOURNEY
= 2/6 = (1/3) HRS TIME TAKEN FOR THE RETURN JOURNEY
= 2/4 = (1/2) HRS TOTAL TIME = 5/6 HRS AVERAGE SPEED = 4/(5/6) = 24/5 = 4.8KMPH
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TIME TAKEN FOR THE FORWARD JOURNEY
= 2/6 = (1/3) HRS TIME TAKEN FOR THE RETURN JOURNEY
= 2/4 = (1/2) HRS TOTAL TIME = 5/6 HRS AVERAGE SPEED = 4/(5/6) = 24/5 = 4.8KMPH
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