Speed Time And Distance(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

SPEED TIME AND DISTANCE MCQs

Time And Distance, Time & Distance, Speed Time & Distance

Total Questions : 1223 | Page 122 of 123 pages

Question 1211. A man travels from A to B at a speed of 30 kmph and returns with a speed of 60 kmph. What is the average speed of the man?

47.5
50
45
40

Discuss Question

Answer: Option D. -> 40
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Question 1212. Two trains 120 miles apart travel towards each other. The 1st train travels at 70 mph while the 2nd at 50 mph. A bird starts flying from the location of the faster train towards the other train at 85 mph and when it reaches the slower train it turns back and flies in the other direction at the same speed. When it reaches the faster train it again turns around and repeats the same procedure again and again. When the train collide, how far will the bird have flown?

85 miles
70 miles
50 miles
120 miles

Discuss Question

Answer: Option A. -> 85 miles
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Question 1213. Danish his car at a speed of 120 kmph for the first 2 hours and then at a speed of 100 kmph for the next half an hour. Find the distance covered by him during the entire journey.

300 km
290 km
250 km
240 km

Discuss Question

Answer: Option B. -> 290 km
TOTAL DISTANCE = (120*2) + (100*(1/2)) = 290 KM

Question 1214. Atif and Bilal, 110 km apart, start cycling towards each other. If Atif covers a distance of 6 km to Bilal’s 5 km, how far will Atif have travelled when they meet?

66 km
55 km
50 km
60 km

Discuss Question

Answer: Option D. -> 60 km
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Question 1215. A train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of journey.

30 km
40 km
70 km
80 km

Discuss Question

Answer: Option C. -> 70 km
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Question 1216. Barkat is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph; he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M. ?

8 kmph
11 kmph
12 kmph
14 kmph

Discuss Question

Answer: Option C. -> 12 kmph
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Question 1217. A boy goes to his school from his house at a speed of 3 km / hr and returns at a speed of 2 km / hr. If he takes 5 hours in going and coming, the distance between his house and school is :___________?

5 km
5.5 km
6 km
6.5 km

Discuss Question

Answer: Option C. -> 6 km
AVERAGE SPEED = ( 2 X 3 X 2/3 + 2 ) KM/ HR = 12/5 KM/ HR. DISTANCE TRAVELLED = ( 12/5 X 5 )KM = 12 KM. SO DISTANCE BETWEEN HOUSE AND SCHOOL = ( 12/2 )KM = 6 KM.

Question 1218. An express train travelled at an average speed of 100 km / hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point ?

6 hrs 21 min
6 hrs 24 min
6 hrs 27 min
6 hrs 30 min

Discuss Question

Answer: Option A. -> 6 hrs 21 min
TIME TAKEN TO COVER 600 KM = ( 600/100 ) HRS = 6 HRS. NUMBER OF STOPPAGES = ( 600/75 – 1 ) = 7 TOTAL TIME OF STOPPAGE = (3 X 7) MIN = 21 MIN. HENCE, TOTAL TIME TAKEN = 6 HRS 21 MIN.

Question 1219. A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km /hr, the time taken by it to cover the same distance will be :__________?

10 min
11 min 20 sec
13 min
13 min 20 sec

Discuss Question

Answer: Option D. -> 13 min 20 sec
SPEED = (10 X 60/12 ) KM/HR = 50 KM/HR. NEW SPEED = (50 – 5) KM / HR = 45 KM /HR. SO TIME TAKEN = ( 10/45 ) HR = ( 2/9X 60 )MIN 131/3 MIN = 13 MIN 20 SEC.

Question 1220. Two automobiles are 150 kilometers apart and traveling toward each other. One automobile is moving at 60km/h and the other is moving at 40km/h mph. In how many hours will they meet?

2.5
2.0
1.75
1.5
1.25

Discuss Question

Answer: Option D. -> 1.5
ONE MOVES AT 60KM/H, SO IN AN HOUR, HE’LL TRAVEL 60KM
THE OTHER MOVES AT 40KM/H, SO IN AN HOUR, HE’LL TRAVEL 40KM
THIS IS TOWARDS EACH OTHER, SO, IN AN HOUR, WE CAN SAY THAT THEY’LL GET 60+40=100KM CLOSER.
THIS MEANS THAT THEY GET CLOSER AT 100KM/H
GIVEN THAT WE HAVE THE DISTANCE OF 150KM, AND THE SPEED OF CLOSURE AT 100KMH, WE CAN NOW USE THE EQUATION
S=D/T
REARRANGE TO FIND T (TIMES BOTH SIDES BY T)
S X T = D (NOW DIVIDE BOTH SIDES BY S)
T=D/S
TIME = 150KM DIVIDED BY 100KM/H
TIME = 1.5 HOURS
OR ONE HOUR AND 30 MINUTES