Question
Two trains 140 metres and 120 metres are running in the same direction with speeds 40 kmph and 60 kmph respectively. In what time will the faster train pass the slower one?
Answer: Option C
TOTAL DISTANCE = ADDITION OF LENGTH OF THE TWO TRAINS = 140 + 120 = 260 METRES
AS THE TWO TRAINS ARE TRAVELLING IN THE SAME DIRECTION, THEIR RELATIVE SPEED IS:
V = | V1 – V2 | = | 40 – 60 | = 20 KM/HR = 20*1000/60 = 1000/3 METRES/MIN
T = 260/ 1000*3
T = 0.78 MINUTES
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TOTAL DISTANCE = ADDITION OF LENGTH OF THE TWO TRAINS = 140 + 120 = 260 METRES
AS THE TWO TRAINS ARE TRAVELLING IN THE SAME DIRECTION, THEIR RELATIVE SPEED IS:
V = | V1 – V2 | = | 40 – 60 | = 20 KM/HR = 20*1000/60 = 1000/3 METRES/MIN
T = 260/ 1000*3
T = 0.78 MINUTES
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