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MCQs

Total Questions : 89 | Page 2 of 9 pages
Question 11. Choose the correct statement for the lambda ZAP vector.
  1.    It is not based on bacteriophage lambda
  2.    It contains a region that can be excised in vivo
  3.    The excision leads to the formation of bluescript plasmids and it contains an initiator region only
  4.    The multiple cloning site is not flanked by the initiator and the terminator region
 Discuss Question
Answer: Option B. -> It contains a region that can be excised in vivo
Answer: (b).It contains a region that can be excised in vivo
Question 12. Choose the correct statement for cosmids.
  1.    It can be regarded as lambda substitution vector
  2.    Less amount of phage DNA is deleted
  3.    Only cos packaging sites are left
  4.    It doesn’t contains a origin of replication
 Discuss Question
Answer: Option C. -> Only cos packaging sites are left
Answer: (c).Only cos packaging sites are left
Question 13. Which of the following doesn’t takes place after replication?
  1.    The single stranded sequence is generated
  2.    It is circularized to form closed single stranded molecule
  3.    It may circularize or remain linear
  4.    The double stranded molecule can be synthesized by cellular DNA synthesis
 Discuss Question
Answer: Option C. -> It may circularize or remain linear
Answer: (c).It may circularize or remain linear
Question 14. The initiator is recognized by which gene?
  1.    Gene I
  2.    Gene I and II
  3.    Only gene II
  4.    Gene III
 Discuss Question
Answer: Option C. -> Only gene II
Answer: (c).Only gene II
Question 15. Choose the incorrect statement for the replication process.
  1.    The initiator site is nicked and replication of one strand is started
  2.    Replication takes place in both the directions
  3.    Replication continues through the bluescript
  4.    It is stopped at the terminator and then again a nick is made
 Discuss Question
Answer: Option B. -> Replication takes place in both the directions
Answer: (b).Replication takes place in both the directions
Question 16. Which of the following is a restriction for cloning in bacteriophage Mu?
  1.    It is limited to handling only small number of phage particles
  2.    It relies on whether the DNA is flanked by two mini Mu genes or not
  3.    Recombination between the elements in the second strain is not a restriction
  4.    Fragments of any genomic DNA can be cloned irrespective of the fact whether or not the phage can replicate in it or not
 Discuss Question
Answer: Option B. -> It relies on whether the DNA is flanked by two mini Mu genes or not
Answer: (b).It relies on whether the DNA is flanked by two mini Mu genes or not
Question 17. What is the function of the pac site in the bacteriophage PI?
  1.    It is responsible for the initiation of packaging
  2.    It is responsible for the termination of packaging
  3.    It is responsible for the initiation of replication
  4.    It is responsible for the termination of replication
 Discuss Question
Answer: Option A. -> It is responsible for the initiation of packaging
Answer: (a).It is responsible for the initiation of packaging
Question 18. What is the function of loxP sites?
  1.    It is responsible for linearization of DNA in the host bacterium
  2.    It is responsible for circularization of DNA in the host bacterium
  3.    It is responsible for conversion of single stranded DNA into double stranded DNA
  4.    It is responsible for conversion of double stranded DNA into single stranded DNA
 Discuss Question
Answer: Option B. -> It is responsible for circularization of DNA in the host bacterium
Answer: (b).It is responsible for circularization of DNA in the host bacterium
Question 19. Which of the following is not included as a step in cloning in bacteriophage PI?
  1.    The growth of vector is done as a plasmid by using pBR322 origin of replication
  2.    Cleaving with BamH1 is done and then products cleaved with Sau3A are ligated
  3.    Incubation with mutant lysogen is done which doesn’t cleaves the recombinants at pac sites
  4.    Incubation is done with mutant lysogen which doesn’t contains head and tail proteins
 Discuss Question
Answer: Option C. -> Incubation with mutant lysogen is done which doesn’t cleaves the recombinants at pac sites
Answer: (c).Incubation with mutant lysogen is done which doesn’t cleaves the recombinants at pac sites
Question 20. What is the size of the insert that can be accommodated in the head of bacteriophage PI?
  1.    30-40 kbp
  2.    80-95 kbp
  3.    110-115 kbp
  4.    200-300 kbp
 Discuss Question
Answer: Option C. -> 110-115 kbp
Answer: (c).110-115 kbp

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