Question
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in___________?
Answer: Option C
(A.+ B)’S 1 DAY’S WORK = ( 1/15 + 1/10 ) = 1/6 WORK DONE BY A AND B IN 2 DAYS = ( 1/6 X 2 ) = 1/3 REMAINING WORK = ( 1 – 1/6 ) = 2/3
NOW, 1/15 WORK IS DONE BY A IN 1 DAY. SO 2/3 WORK WILL BE DONE BY A IN ( 15 X 2/3 ) = 10 DAYS HENCE, TOTAL TIME TAKEN = (10 + 2) = 12 DAYS.
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(A.+ B)’S 1 DAY’S WORK = ( 1/15 + 1/10 ) = 1/6 WORK DONE BY A AND B IN 2 DAYS = ( 1/6 X 2 ) = 1/3 REMAINING WORK = ( 1 – 1/6 ) = 2/3
NOW, 1/15 WORK IS DONE BY A IN 1 DAY. SO 2/3 WORK WILL BE DONE BY A IN ( 15 X 2/3 ) = 10 DAYS HENCE, TOTAL TIME TAKEN = (10 + 2) = 12 DAYS.
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