Answer: Option C. -> 1.2 days
TIME IS
DIRECTLY PROPORTIONAL TO NUMBER OF SOFAS
INVERSELY PROPORTIONAL TO NUMBER OF PEOPLE NO. OF DAYS
= (6/8)*(8/10)*2
= 1.2 DAYS

Answer: Option C. -> 16 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option D. -> 18 men
FOR THE WORK TO BE COMPLETED IN 9 DAYS,
6 MEN ARE REQUIRED. TIME AND MEN ARE INVERSELY PROPORTIONAL. FOR THE WORK TO BE COMPLETED IN 3 DAYS,
6*9/3 = 18 MEN ARE REQUIRED

Answer: Option C. -> 10
10 WORKERS MAKE 10 TABLES IN 10 DAYS. 1 WORKER MAKES 1 TABLE IN 10 DAYS. SIMILARLY, 5 WORKERS CAN MAKE 5 TABLES IN 10 DAYS.

Answer: Option A. -> Rs.1104
ASSUME THAT COST OF KEEPING A COW FOR 1 DAY = C ,
COST OF KEEPING A GOAT FOR 1 DAY = G
COST OF KEEPING 20 COWS AND 40 GOATS FOR 10 DAYS = 460
COST OF KEEPING 20 COWS AND 40 GOATS FOR 1 DAY = 460/10 = 46
=> 20C + 40G = 46
=> 10C + 20G = 23 —(1)
GIVEN THAT 5G = C
HENCE EQUATION (1) CAN BE WRITTEN AS 10C + 4C = 23 => 14C =23
=> C=23/14
COST OF KEEPING 50 COWS AND 30 GOATS FOR 1 DAY
= 50C + 30G
= 50C + 6C (SUBSTITUTED 5G = C)
= 56 C = 56×23/14
= 92
COST OF KEEPING 50 COWS AND 30 GOATS FOR 12 DAYS = 12×92 = 1104

Answer: Option A. -> 15 days
RAIO OF TIMES TAKEN BY A AND B = 1 : 3
IF THE DIFFERENCE OF TIME IS 2 DAYS, B TAKES 3 DAYS. IF THE DIFFERENCE OF TIME IS 10 DAYS.
B TAKES [3/2×10]=15 DAYS

Answer: Option D. -> 6
LET P TAKES X DAYS TO COMPLETE THE WORK
THEN Q TAKES X/2 DAYS AND R TAKES X/3 DAYS TO FINISH THE WORK
AMOUNT OF WORK P DOES IN 1 DAY = 1/X
AMOUNT OF WORK Q DOES IN 1 DAY = 2/X
AMOUNT OF WORK R DOES IN 1 DAY = 3/X
AMOUNT OF WORK P,Q AND R DO IN 1 DAY = 1/X + 2/X + 3/X = 1/X (1 + 2 + 3) = 6/X
6/X = 2
=> X = 12
=> Q TAKES 12/2 DAYS = 6 DAYS TO COMPLETE THE WORK

Answer: Option B. -> 20 min
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option C. -> 40
WORK DONE BY 4 MEN AND 6 WOMEN IN 1 DAY = 1/8
WORK DONE BY 3 MEN AND 7 WOMEN IN 1 DAY = 1/10
LET 1 MAN DOES M WORK IN 1 DAY AND 1 WOMAN DOES W WORK IN 1 DAY. THE ABOVE EQUATIONS CAN BE WRITTEN AS
4M + 6W = 1/8 —(1)
3M + 7W = 1/10 —(2)
SOLVING EQUATION (1) AND (2) , WE GET M=11/400 AND W=1/400
AMOUNT OF WORK 10 WOMEN CAN DO IN A DAY = 10 × (1/400) = 1/40
IE, 10 WOMEN CAN COMPLETE THE WORK IN 40 DAYS

Answer: Option C. -> 15 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!