Mensuration(6th Grade > Mathematics ) Questions and answers for exam Preparation

6th Grade > Mathematics

MENSURATION MCQs

Total Questions : 95 | Page 5 of 10 pages

Question 41. The idea of perimeter plays an important for ____.

a farmer who wants to fence his land
a farmer who wants to plough his land
a farmer who wants to excavate his land
a farmer who wants to water his land

Discuss Question

Answer: Option A. -> a farmer who wants to fence his land
:
A
In order to fence a land, a farmer needs the total length of the boundary which is given by theperimeter.
For ploughing and watering theland, a farmer needs the area of the field, and for excavating the land the farmer will need the volume of the soil excavated.

Question 42. Which of the following is not the unit of area?

Discuss Question

Answer: Option D. -> m3
:
D
Among the given options,

m^{2}

c m^{2}

and

k m^{2}

are all units of area while

m^{3}

is a unit of volume.
Hence,

m^{3}

is not a unit of area.

Question 43. The length of a rectangle is 10 cm and width is 7 cm. What will be the area of a rectangle formed by joining 12 such rectangles?

840 cm2
70 cm
680 cm2
460 cm

Discuss Question

Answer: Option A. -> 840 cm2
:
A
Area of a rectangle = Length

\times

Breadth

= 10 \times 7

= 70 c m^{2}

When we join several figures, the area of the figure formed is the sum of areas of the figures joined.
Hence, area of the larger rectangle

= 12 \times 70

= 840 c m^{2}

Question 44. The area of the given figure will be

94 sq.units
66 sq.units
90 sq.units
93 sq.units

Discuss Question

Answer: Option B. -> 66 sq.units
:
B

The area of the figure is the sum of areasof all rectangles formingthe figure.
Looking at the figure there are 4 rectangles, 3 rectangles of dimensions 3 m and 4m and 1 rectangle of dimensions 3 m and 7 m.

∴

Area = (3

\times

4)+ (3

\times

4) + (3

\times

4) + (3

\times

7) + (3

\times

3)
= 12 + 12 + 12 +21 + 9
= 66 sq. units

Question 45. The area of the given figure (all dimensions in units) will be

46 sq. units
60 sq. units
36 sq. units
63 sq. units

Discuss Question

Answer: Option C. -> 36 sq. units
:
C
On dividing the figure into squares and rectangle, it will look like:

The are of figure is sum of areas of square 1 and rectangles 2 and 3.
=(1x 1) + ( 4x 5) + (3x 5)
= 1+ 20+ 15
= 36 sq. units

Question 46.

Find the area of a rectangle whose length is 4 cm and its breadth is 3 cm. [1 MARK]

Discuss Question

Answer: Option C. -> 36 sq. units
:

Solution: 1 Mark
Area of the rectangle = length $\times$ breadth

= 4 \times 3

= 12 {c m}^{2}

Question 47.

What is the area of the table whose sides measure 1m 20 cm in length and 2m 50 cm in breadth? [2 MARKS]

Discuss Question

Answer: Option C. -> 36 sq. units
:
Steps: 1 Mark
Answer: 1 Mark

\Rightarrow

Length (l) = 1m 20cm
1 m= 100 cm
=

(1 + \frac{20}{100}) m = 1.2 m

\Rightarrow

Breadth (b) = 2m 50cm
=

(2 + \frac{50}{100}) m = 2.5 m

\Rightarrow

Area =

l \times b = 1.2 m \times 2.5 m = 3 m^{2}

Question 48.

Find the perimeter and area of the shape given below: [3 MARKS]

Discuss Question

Answer: Option C. -> 36 sq. units
:

Concept: 1 Mark
Application: 1 Mark
Solution: 1 Mark
$\Rightarrow$ Perimeter = Length of the boundary
= (45 + 22 + 25 + 8 + 20 + (8+22))
= (45 + 22 + 25 + 8 + 20 + (30))
= 150m
$\Rightarrow$ Area of the shape = Area of the larger rectangle + area of smaller rectangle
$= (45 \times 22) + (20 \times 8)$
$= (990) + (160)$
$= 1150 {c m}^{2}$
$∴$ Area $= 1150 {c m}^{2}$

Question 49.

Find the area of the following figure (in sq. inches). [2 MARKS]

Discuss Question

Answer: Option C. -> 36 sq. units
:

Steps: 1 Mark
Answer: 1 Mark

Area of the given shape = Area of square + Area of rectangle
= (side) $^{2}$ + (length $\times$ breadth)

$= (3)^{2} + (2 \times 9) = 9 + 18$
$= 27$ sq inches

Question 50.

The blackboard of Akshit's classroom has length 6m and its width is 5m. If it has to be framed by a steel plate at the borders, then what will be the length of steel plate required? [3 MARKS]

Discuss Question

Answer: Option C. -> 36 sq. units
:

Steps: 1 Mark
Formula: 1 Mark
Answer: 1 Mark
The perimeter of the blackboard = Length of the steel plate required.
Perimeter of a rectangle $= 2 \times (L + B)$ .
Length of steel plate
= $2 \times (6 + 5) = 2 \times 11 = 22 m$