Width of rectangle = $\frac{11}{2}cm$
Area of rectangle= length $\times$ Width
= $\frac{11}{2}\times 11$
= 60.5  $c{m}^2$

Perimeter = Sum of lengths of all sides
$\therefore$ Perimeter of the given figure = 4.3 mm + 1.52 mm + 5.4 mm + 9.2 mm + 3.1 mm + 4.2 mm
= 27.72 mm

In the given figure, sides FE and ED are unknown.
Now, FE + GH + CD = AB = 5.6 cm 
$\Rightarrow$ 1.2 + 0.8 + FE = 5.6
$\Rightarrow$ FE = 3.6 cm
GF = ED = 5.8 cm and AH = BC = 6.4  cm 

Perimeter of the figure is sum of all sides
= HG + GF + FE + ED + DC + CB + BA + AH 
= 1.2 cm + 5.8  cm + 3.6  cm + 5.8  cm + 0.8  cm + 6.4  cm + 5.6  cm + 6.4  cm 
= 35.6 cm 

Area of rectangle = length $\times$ breadth

$\therefore$ 36 = 4 $\times$ breadth

$\Rightarrow \frac{36}{4}$ = breadth

$\Rightarrow$ breadth = 9 cm

Given, side of the square plot = 13 m
We know that, area of a square = Side x Side
So, total area of a square
= Side $\times$ Side
= 13 x 13 = 169 $m^2$

Area on which grass is grown = Half of the total area
= $\frac{169}{2}$ = 84.5 $m^2$

In order to fence a land, a farmer needs the total length of the boundary which is given by the perimeter.

For ploughing and watering the land, a farmer needs the area of the field, and for excavating the land the farmer will need the volume of the soil excavated.

Among the given options, $m^2$, $c{m}^2$ and $k{m}^2$ are all units of area while $m^3$ is a unit of volume.
Hence, $m^3$ is not a unit of area.

The amount of surface enclosed by a closed figure is called its area. An area expresses the extent of a two-dimensional figure.

Given, perimeter of a square land = 20 m
Perimeter of a square = 4 $\times$ Side of the square
$\therefore$ 20 = 4 $\times$ side
$\Rightarrow$ Side = $\frac{20}{4}$
             = 5 m
$\because$ Cow is standing at centre of the square, in order to go out it has to travel the length equal to half of the side =$\frac{5}{2}$
        = 2.5 m

Area of a rectangle = Length $\times$ Breadth
                                $=10\times 7$
                                $=70c{m}^2$
When we join several figures, the area of the figure formed is the sum of areas of the figures joined.
Hence, area of the larger rectangle
$=12\times 70$
$=840c{m}^2$