6th Grade > Mathematics
MENSURATION MCQs
Total Questions : 95
| Page 2 of 10 pages
Answer: Option C. -> closed figure
:
C
The length of the boundary of a closed figure is called its perimeter.
Hence, perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.
:
C
The length of the boundary of a closed figure is called its perimeter.
Hence, perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.
Answer: Option D. -> open figures
:
D
Perimeter is basically the total length of the boundary of afigure. This is valid for closed figures only (both regular and irregular).
:
D
Perimeter is basically the total length of the boundary of afigure. This is valid for closed figures only (both regular and irregular).
Answer: Option C. -> 120 cm
:
C
Perimeter = Sum of all the sides
Sinceit is a regular octagon, all sides will be equal.
∴ Perimeter = 8 × length of a side
= 8× 15 cm
= 120 cm
:
C
Perimeter = Sum of all the sides
Sinceit is a regular octagon, all sides will be equal.
∴ Perimeter = 8 × length of a side
= 8× 15 cm
= 120 cm
Answer: Option B. -> 60 cm
:
B
Perimeter of square = 4 × length of side
= 4 × 15
= 60 cm
:
B
Perimeter of square = 4 × length of side
= 4 × 15
= 60 cm
Answer: Option A. -> Sum of lengths of sides
:
A
The perimeter of a figure is the sum of lengths of all sides. In other words, perimeter is the distance covered along the boundary of the figure when you go round the figure once.
:
A
The perimeter of a figure is the sum of lengths of all sides. In other words, perimeter is the distance covered along the boundary of the figure when you go round the figure once.
Answer: Option C. -> 72
:
C
Given a square room of side = 6 m.
Area of each tile = 0.5 m2
We know that, area of a square = Side × Side
∴ Area of a square room
= 6 × 6 = 36 m2.
So, number of tiles required
= Area of roomArea of a single tile
= 360.5= 72
Hence, Karanshouldbuy 72 tilesto cover the floor of his room.
:
C
Given a square room of side = 6 m.
Area of each tile = 0.5 m2
We know that, area of a square = Side × Side
∴ Area of a square room
= 6 × 6 = 36 m2.
So, number of tiles required
= Area of roomArea of a single tile
= 360.5= 72
Hence, Karanshouldbuy 72 tilesto cover the floor of his room.
Answer: Option B. -> 35.6 cm
:
B
In the given figure, sides FE and ED are unknown.
Now, FE + GH + CD = AB = 5.6 cm
⇒ 1.2 + 0.8 + FE = 5.6
⇒ FE = 3.6 cm
GF = ED = 5.8 cm and AH = BC = 6.4cm
Perimeter of the figure is sum of all sides
= HG + GF + FE + ED + DC + CB + BA + AH
= 1.2cm + 5.8cm + 3.6cm + 5.8cm + 0.8cm + 6.4cm + 5.6cm + 6.4 cm
=35.6 cm
:
B
In the given figure, sides FE and ED are unknown.
Now, FE + GH + CD = AB = 5.6 cm
⇒ 1.2 + 0.8 + FE = 5.6
⇒ FE = 3.6 cm
GF = ED = 5.8 cm and AH = BC = 6.4cm
Perimeter of the figure is sum of all sides
= HG + GF + FE + ED + DC + CB + BA + AH
= 1.2cm + 5.8cm + 3.6cm + 5.8cm + 0.8cm + 6.4cm + 5.6cm + 6.4 cm
=35.6 cm
Answer: Option C. -> 9 cm
:
C
Area of rectangle = length × breadth
∴ 36 = 4 × breadth
⇒364 = breadth
⇒breadth = 9 cm
:
C
Area of rectangle = length × breadth
∴ 36 = 4 × breadth
⇒364 = breadth
⇒breadth = 9 cm
Answer: Option C. -> a triangle and a pentagon.
:
C
The given figure has two parts, the lower part is a triangle and the upper part is a pentagon.
:
C
The given figure has two parts, the lower part is a triangle and the upper part is a pentagon.
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