6th Grade > Mathematics
MENSURATION MCQs
:
Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark
The perimeter of an equilateral triangle:
= 3 × length of a side.
The total distance to be painted:
= 3 × 4 = 12 km
⇒ Hence, the total cost for painting:
= 250 × 12
= Rs 3000
⇒ Area of the garden
= 12× base × height.
= 12×42×3.46
= 3.46 km2
:
Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark
(i) Let l be the length of the square
⇒ Area of square = l2
⇒l2=576
⇒l=24 m
(ii) Perimeter of square = 4l
⇒4×(24)=96 m
(iii) Cost of fixing a fence
=₹(96×3.20)=₹307.20
:
Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark
The area of the figure can be calculated in three steps:
i) Find the area of the small rectangle.
ii) Find the area of the large rectangle.
iii) Find the area of the triangle
i) Area of the small rectangle:
= length × breadth
= 5 × 6
= 30 inches2
ii) Area of the large rectangle:
= 12 × 4
= 48 inches2
iii) Area of the triangle:
= 12× (height × base)
= 12× 4 × 3 = 6 inches2
Area of the shape = Area of the small rectangle + Area of the large rectangle + Area of the triangle
= (30 + 48 + 6) inches2= 84 inches2
:
Each Option: 2 Marks
(a) Area of a rectangular garden:
= length × breadth = 18
= 3 × breadth
⇒ breadth = 183
= 6 m
(b) Perimeter = 2 × (length + breadth)
= 2 × (3+6) = 18m2
:
C
The given figure has two parts, the lower part is a triangle and the upper part is a pentagon.
:
B
Given figure is an irregular figure, for which the number of sides cannot be found out. The figure is also a closed one.
:
C
The given figure has a total of 12 sides (AB, BC, CD, DE, EF, FG, GH, HI, IJ, JK, KL and LA). In order to complete a full round, one should reach the same corner one started from. So, we have to cover 12 sides.
:
The perimeter is the total length of the boundary of the closed figure. For a square, it is basically the sum of all the sides and in a square, all sides are equal. So, the perimeter is 4 x sides.
:
The sum of all the sides of a closed figure is termed its perimeter.