Mensuration(6th Grade > Mathematics ) Questions and answers for exam Preparation

6th Grade > Mathematics

MENSURATION MCQs

Total Questions : 95 | Page 3 of 10 pages

Question 21. The area of the rectangle with length 11 cm and width equal to half its length will be

22 cm2
33 cm2
60.5 cm
60.5 cm2

Discuss Question

Answer: Option D. -> 60.5 cm2
:
D
Width of rectangle =

\frac{11}{2} c m

Area of rectangle= length

\times

Width
=

\frac{11}{2} \times 11

= 60.5

c m^{2}

Question 22. Find the perimeter of the following figure (all measurements are in mm):

128.82 mm
26.72 cm
27.72 mm
27.72 cm

Discuss Question

Answer: Option C. -> 27.72 mm
:
C
Perimeter = Sum of lengths of all sides

∴

Perimeter of the given figure = 4.3 mm + 1.52 mm + 5.4 mm + 9.2 mm + 3.1 mm + 4.2 mm
= 27.72 mm

Question 23. The perimeter of a square is ___ times the length of its side.

Discuss Question

:
The perimeter is the total length of the boundary of the closed figure. For a square, it is basically the sum of all the sides and in a square, all sides are equal. So, the perimeter is 4 xsides.

Question 24. The sum of all the sides of a closed figure is called its ___.

Discuss Question

:
The sum of all the sides of a closed figure is termed its perimeter.

Question 25. There is a square plot with side length equal to 13 m. A farmer wanted to grow grass on half his field and plough the remaining land. Find the area of land used to grow the grass.

84.5 m2
169 m2
52 m2
84.5 m

Discuss Question

Answer: Option A. -> 84.5 m2
:
A
Given, side of the square plot = 13 m
We know that, area of a square = Side x Side
So, total area of a square
= Side

\times

Side
= 13 x 13 = 169

m^{2}

Area on which grass is grown = Half of the total area
=

\frac{169}{2}

= 84.5

m^{2}

Question 26. Find the area of the following figure (in sq. inches). [2 MARKS]

Discuss Question

:
Steps: 1 Mark
Answer: 1 Mark

Areaofthegivenshape=Areaofsquare+Areaofrectangle
= (side)

^{2}

+ (length

\times

breadth)

= (3)^{2} + (2 \times 9) = 9 + 18

= 27

sq inches

Question 27. Find the perimeter and area of the shape given below: [3 MARKS]

Discuss Question

:
Concept: 1 Mark
Application: 1 Mark
Solution: 1 Mark

\Rightarrow

Perimeter = Length of the boundary
= (45 + 22 + 25 + 8 + 20 + (8+22))
=(45 + 22 + 25 + 8 + 20 + (30))
= 150m

\Rightarrow

Area of the shape = Area of the larger rectangle + area of smaller rectangle

= (45 \times 22) + (20 \times 8)

= (990) + (160)

= 1150 {c m}^{2}

∴

Area

= 1150 {c m}^{2}

Question 28. Pratik and his friends were playing around a track that is shaped like a regular hexagon. Each side measures 45 feet. If they make 2 complete trips around the track, how far will they have walked? [3 MARKS]

Discuss Question

:
Steps: 1 Mark
Formula: 1 Mark
Answer: 1 Mark
The perimeter of a regular hexagon
=