Question
Answer:
:
Concept: 1 Mark
Application: 1 Mark
Solution: 1 Mark
⇒ Perimeter = Length of the boundary
= (45 + 22 + 25 + 8 + 20 + (8+22))
=(45 + 22 + 25 + 8 + 20 + (30))
= 150m
⇒ Area of the shape = Area of the larger rectangle + area of smaller rectangle
=(45×22)+(20×8)
=(990)+(160)
=1150cm2
∴ Area=1150cm2
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:
Concept: 1 Mark
Application: 1 Mark
Solution: 1 Mark
⇒ Perimeter = Length of the boundary
= (45 + 22 + 25 + 8 + 20 + (8+22))
=(45 + 22 + 25 + 8 + 20 + (30))
= 150m
⇒ Area of the shape = Area of the larger rectangle + area of smaller rectangle
=(45×22)+(20×8)
=(990)+(160)
=1150cm2
∴ Area=1150cm2
Was this answer helpful ?
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