Question
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
Answer: Option C
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A's 1 hour's work = \(\frac{1}{4}\) ,
(B + C)'s 1 hour's work = \(\frac{1}{3}\) ,
(A + C)'s 1 hour's work = \(\frac{1}{2}\) ,
(A + B + C)'s 1 hour's work = \(\left(\frac{1}{4}+\frac{1}{3}\right)=\frac{7}{12}.\)
B's 1 hour's work = \(\left(\frac{7}{12}-\frac{1}{2}\right)=\frac{1}{12}.\)
So, B alone will take 12 hours to do the work.
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