A can finish a work in 18 days and B can do the same work in 15 days. B worked f

Question

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

Options:

A . 5

B . \(5\frac{1}{2}\)

C . 6

D . 8

Answer: Option C

B's 10 day's work = \(\left(\frac{1}{5}\times10\right) = \frac{2}{3}.\)

Remaining work = \( \left(1-\frac{2}{3}\right) = \frac{1}{3}\)

Now, \(\frac{1}{18}\) work is done by A in 1 day.

So, \(\frac{1}{3}\) work is done by A in \( \left(18\times\frac{1}{3}\right)\) = 6 days.

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