Question
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Answer: Option B
Was this answer helpful ?
Work done by X in 4 days = \(\left(\frac{1}{20}\times4\right)=\frac{1}{5}\)
Remaining work = \(\left(1-\frac{1}{5}\right) =\frac{4}{5}\)
(X + Y)'s 1 day's work = \(\left(\frac{1}{20}+\frac{1}{12}\right)=\frac{8}{60}=\frac{2}{15}
\)
Now, \(\frac{2}{15}
\) work is done by X and Y in 1 day.
So, \(\frac{4}{5}\) work will be done by X and Y in \(\left(\frac{15}{2}\times\frac{4}{5}\right)= 6 days.\)
Hence, total time taken = (6 + 4) days = 10 days.
Was this answer helpful ?
Submit Solution