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Question

X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

Options:
A .  6 days
B .  10 days
C .  15 days
D .  20 days
Answer: Option B

Work done by X in 4 days = \(\left(\frac{1}{20}\times4\right)=\frac{1}{5}\)


Remaining work = \(\left(1-\frac{1}{5}\right) =\frac{4}{5}\)


(X + Y)'s 1 day's work = \(\left(\frac{1}{20}+\frac{1}{12}\right)=\frac{8}{60}=\frac{2}{15}
\)


Now, \(\frac{2}{15}
\)
  work is done by X and Y in 1 day.


So,  \(\frac{4}{5}\)  work will be done by X and Y in \(\left(\frac{15}{2}\times\frac{4}{5}\right)= 6 days.\)


Hence, total time taken = (6 + 4) days = 10 days.


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