Question
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Answer: Option C
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(A + B)'s 1 day's work = \(\frac{1}{10}\)
C's 1 day's work = \(\frac{1}{50}\)
(A + B + C)'s 1 day's work = \(\left(\frac{1}{10}+\frac{1}{50}\right)=\frac{6}{50}= \frac{3}{25}. ......(i)\)
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) = \(\frac{3}{25}\)
A's 1 day's work = \(\frac{3}{50}\)
So, B's 1 day's work \(\left(\frac{1}{10}-\frac{3}{50}\right)=\frac{2}{50} = \frac{1}{25}.\)
So, B alone could do the work in 25 days.
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