Question
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option D
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(A + B)'s 20 day's work = \(\left(\frac{1}{30}\times20\right) = \frac{2}{3}.\)
Remaining work = \(\left(1-\frac{2}{3}\right) = \frac{1}{3}.\)
Now, \(\frac{1}{3}\) work is done by A in 20 days.
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
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