Quantitative Aptitude
SPEED TIME AND DISTANCE MCQs
Time & Distance
Total Questions : 422
| Page 6 of 43 pages
Answer: Option B. -> 16.4
Answer: (b)Let the total journey be of x km, then${2x}/15 + {9x}/20 + 10 = x$$x - {2x}/15 - {9x}/20$ = 10${60x - 8x - 27x}/60$ = 10${25x}/60$ = 10$x = {60 × 10}/25$ = 24 km
Answer: (b)Let the total journey be of x km, then${2x}/15 + {9x}/20 + 10 = x$$x - {2x}/15 - {9x}/20$ = 10${60x - 8x - 27x}/60$ = 10${25x}/60$ = 10$x = {60 × 10}/25$ = 24 km
Answer: Option D. -> 6 hours
Answer: (d)Total distance covered= Speed × Time= 40 × 9 = 360 km.The required time at 60 kmph= $360/60 = 6$ hours. Using Rule 9,Speed(s) ∝ $1/{time (t)}$ ⇒ s ∝ $1/t$$s_1t_1 = s_2t_2$(Provided distance is constant)
Answer: (d)Total distance covered= Speed × Time= 40 × 9 = 360 km.The required time at 60 kmph= $360/60 = 6$ hours. Using Rule 9,Speed(s) ∝ $1/{time (t)}$ ⇒ s ∝ $1/t$$s_1t_1 = s_2t_2$(Provided distance is constant)
Answer: Option A. -> 6.30 a.m.
Answer: (a)Difference of time= 4.30 p.m - 11.a.m.= $5{1}/2$ hours $11/2$ hoursDistance covered in $11/2$ hrs= $5/6 - 3/8 = {20 - 9}/24 = 11/24$ partSince, $11/24$ part of the journey is covered in $11/2$ hours$3/8$ part of the journey is covered in= $11/2 × 24/11 × 3/8$= $9/2$ hours = 4$1/2$ hours.Clearly the person started at 6.30 a.m.
Answer: (a)Difference of time= 4.30 p.m - 11.a.m.= $5{1}/2$ hours $11/2$ hoursDistance covered in $11/2$ hrs= $5/6 - 3/8 = {20 - 9}/24 = 11/24$ partSince, $11/24$ part of the journey is covered in $11/2$ hours$3/8$ part of the journey is covered in= $11/2 × 24/11 × 3/8$= $9/2$ hours = 4$1/2$ hours.Clearly the person started at 6.30 a.m.
Answer: Option C. -> 7 km/hr
Answer: (c)Time taken to cover 30km at 6 kmph= $30/6$ = 5 hoursTime taken to cover 40 km = 5 hoursAverage speed= $\text"Total distance"/ \text"Total time"$= ${30 + 40}/10 = 70/10 = 7$ kmph
Answer: (c)Time taken to cover 30km at 6 kmph= $30/6$ = 5 hoursTime taken to cover 40 km = 5 hoursAverage speed= $\text"Total distance"/ \text"Total time"$= ${30 + 40}/10 = 70/10 = 7$ kmph
Answer: Option D. -> 45 km/hr
Answer: (d)Using Rule 2,If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed= $\text"total travelled distance"/\text"total time taken in travelling distance"$= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$
Answer: (d)Using Rule 2,If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed= $\text"total travelled distance"/\text"total time taken in travelling distance"$= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$
Answer: Option C. -> 48 km/h
Answer: (c)Here, distance is same.Average speed = ${2xy}/{x + y}$= $({2 × 40 × 60}/{40 + 60})$ kmph.= $({2 × 40 × 60}/100)$ kmph.= 48 kmph.
Answer: (c)Here, distance is same.Average speed = ${2xy}/{x + y}$= $({2 × 40 × 60}/{40 + 60})$ kmph.= $({2 × 40 × 60}/100)$ kmph.= 48 kmph.
Answer: Option C. -> 68 kmph
Answer: (c)Difference of time= 5 + 3 = 8 minutes= $8/60$ hour = $2/15$ hourIf the speed of motorbike be x kmph, then$25/50 - 25/x = 2/15$$25/x = 1/2 - 2/15$$25/x = {15 - 4}/30 = 11/30$11x = 25 × 30$x = {25 × 30}/11 = 750/11$= 68.18 kmph ≈ 68 kmph
Answer: (c)Difference of time= 5 + 3 = 8 minutes= $8/60$ hour = $2/15$ hourIf the speed of motorbike be x kmph, then$25/50 - 25/x = 2/15$$25/x = 1/2 - 2/15$$25/x = {15 - 4}/30 = 11/30$11x = 25 × 30$x = {25 × 30}/11 = 750/11$= 68.18 kmph ≈ 68 kmph
Answer: Option C. -> 40 km/hr
Answer: (c)Using Rule 5,Here same distances are covered at different speeds.Average speed= $({2xy}/{x + y})$ kmph= $[{2 × 36 × 45}/({36 + 45})]$ kmph= ${2 × 36 × 45}/81$ = 40 kmph
Answer: (c)Using Rule 5,Here same distances are covered at different speeds.Average speed= $({2xy}/{x + y})$ kmph= $[{2 × 36 × 45}/({36 + 45})]$ kmph= ${2 × 36 × 45}/81$ = 40 kmph
Answer: Option A. -> 10.9 kmph
Answer: (a)Here distances are same.∴ Average speed = $({2xy}/{x + y})$ kmph= $({2 × 12 × 10}/{12 + 10})$ kmph= $(240/22)$ kmph = 10.9 kmph
Answer: (a)Here distances are same.∴ Average speed = $({2xy}/{x + y})$ kmph= $({2 × 12 × 10}/{12 + 10})$ kmph= $(240/22)$ kmph = 10.9 kmph
Answer: Option C. -> 30 km/hr
Answer: (c)Using Rule 2,If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed= $\text"total travelled distance"/\text"total time taken in travelling distance"$= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$
Answer: (c)Using Rule 2,If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed= $\text"total travelled distance"/\text"total time taken in travelling distance"$= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$
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