Speed Time And Distance(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

SPEED TIME AND DISTANCE MCQs

Time & Distance

Total Questions : 422 | Page 4 of 43 pages

Question 31. A and B start running at the same time and from the same point around a circle. If A can complete one round in 40 seconds and B in 50 seconds, how many seconds will they take to reach the starting point simultaneously ?

200
2000
90
10

Discuss Question

Answer: Option A. -> 200
Answer: (a)Required time= LCM of 40 and 50 seconds= 200 seconds

Question 32. A runs twice as fast as B and B runs thrice as fast as C. The distance covered by C in 72 minutes, will be covered by A in :

24 minutes
12 minutes
16 minutes
18 minutes

Discuss Question

Answer: Option B. -> 12 minutes
Answer: (b)Ratio of the speed of A, B and C = 6 : 3 : 1Ratio of the time taken= $1/6 : 1/3$ : 1 = 1 : 2 : 6Time taken by A= $72/6$ =12 minutes

Question 33. In a race of 1000 m, A can beat B by 100m. In a race of 400 m, B beats C by 40m. In a race of 500m. A will beat C by

50 m
60 m
45 m
95 m

Discuss Question

Answer: Option D. -> 95 m
Answer: (d)When A runs 1000m, B runs 900m.When A runs 500m, B runs 450 m.Again, when B runs 400m, C runs 360 m.When B runs 450m, C runs= $360/400 × 450$ = 405 metresRequired distance= 500 - 405 = 95 metres

Question 34. A is twice as fast as B, and B is thrice as fast as C is. The journey covered by C in 1$1/2$ hours will be covered by A in

30 minutes
10 minutes
1 hour
15 minutes

Discuss Question

Answer: Option D. -> 15 minutes
Answer: (d)Time taken by C = t hoursTime taken by B = $t/3$ hoursand time taken by A = $t/6$ hoursHere, t = $3/2$ hours∴ Required time taken by A= $3/{2/6}$ hour = $1/4$ hour= $(1/4 × 60)$ minutes = 15 minutes

Question 35. Walking at the rate of 4 kmph a man covers certain distance in 2 hrs 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in how many minutes ?

35 min.
45 min.
40 min.
50 min.

Discuss Question

Answer: Option C. -> 40 min.
Answer: (c)2 hours 45 minutes= $(2 + 45/60)$ hours= $(2 + 3/4)$ hours = $11/4$ hoursDistance = Speed × Time= 4 × $11/4$ = 11 km.Time taken in covering 11 km at 16.5 kmph= $11/{16.5}$ hour= $({11 × 10 × 60}/165)$ minutes= 40 minutes

Question 36. In a race of 800 metres, A can beat B by 40 metres. In a race of 500 metres, B can beat C by 5 metres. In a race of 200 metres, A will beat C by

1.19 metre
1.27 metre
12.7 metre
11.9 metre

Discuss Question

Answer: Option D. -> 11.9 metre
Answer: (d)According to the question,When A runs 800 metres, B runs 760 metresWhen A runs 200 metres, B runs= $760/800 × 200$ = 190 metresAgain, when B runs 500 metres, C runs 495 metres.When B runs 190 metres, C runs= $495/500 × 190$ = 188.1 metres∴ Hence, A will beat C by200 - 188.1 = 11.9 metres in a race of 200 metres.

Question 37. In a race of 200 metres, B can give a start of 10 metres to A, and C can give a start of 20 metres to B. The start that C can give to A, in the same race, is

25 metres
27 metres
29 metres
30 metres

Discuss Question

Answer: Option C. -> 29 metres
Answer: (c)According to the question,Since, When B runs 200 m metres, A runs 190 metresWhen B runs 180 metres, A runs= $190/200 × 180$ = 171 metresWhen C runs 200m, B runs 180 metres.Hence, C will give a start to A by= 200 - 171 = 29 metres

Question 38. In a race of one kilometre, A gives B a start of 100 metres and still wins by 20 seconds. But if A gives B a start of 25 seconds, B wins by 50 metres. The time taken by A to run one kilometre is

$500/29$ seconds
$700/29$ seconds
$1200/29$ seconds
17 seconds

Discuss Question

Answer: Option A. -> $500/29$ seconds
Answer: (a)Let A take x seconds in covering 1000m and b takes y secondsAccording to the question,x + 20 = $900/1000$ yx + 20 = ${9y}/10$ ...(i)and, $950/1000$ x + 25 = y ...(ii)From equation (i),${10x}/9 + 200/9 = y$${10x}/9 + 200/9 = {950x}/1000 + 25$${10x}/9 + 200/9 = {19x}/20 + 25$${10x}/9 - {19x}/20 = 25 - 200/9$${200x - 171x}/180 = {225 - 200}/9$${29x}/180 = 25/9$$x = 25/9 × 180/29 = 500/29$ seconds.

Question 39. In a one-kilometre race A, B and C are the three participants. A can give B a start of 50 m. and C a start of 69 m. The start, which B can allow C is

20 m.
18 m.
19 m.
17 m.

Discuss Question

Answer: Option A. -> 20 m.
Answer: (a)Let the time taken to complete the race by A,B, and C be x minutes.Speed of A = $1000/x$,B = ${1000 - 50}/x = 950/x$C = ${1000 - 69}/x = 931/x$Now, time taken to complete the race byB = $1000/{950/x} = {1000 × x}/950$and distance travelled by C in${1000x}/950$ min = ${1000x}/950 × 931/x$ = 980 km.B can allow C= 1000 - 980 = 20 m

Question 40. A car moving in the morning fog passes a man walking at 4 km/ h. in the same direction. The man can see the car for 3 minutes and visibility is upto a distance of 130 m. The speed of the car is :

5 km. per hour
7 km. per hour
6$3/5$ km. per hour
7$3/5$ km. per hour

Discuss Question

Answer: Option C. -> 6$3/5$ km. per hour
Answer: (c)Speed of car = x kmph.Relative speed = (x - 4) kmph.Time = 3 minutes= $3/60$ hour = $1/20$ hourDistance = 130 metre= $130/1000$ km. = $13/100$ km.Relative speed = $\text"Distance"/ \text"Time"$$x - 4 = 13/100$ × 205x - 20 = 135x = 20 + 13 = 33$x = 33/5 = 6{3}/5$ kmph.