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SPEED TIME AND DISTANCE MCQs

Time & Distance

Total Questions : 422 | Page 1 of 43 pages
Question 1.

A car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. At 10.30 he finds that he has covered only 40% of the distance. By how much he has to increase the speed of the car in order to keep up his schedule?

एक कार चालक सुबह 8.30 बजे बेंगलुरु से निकलता है। और दोपहर 12.30 बजे बेंगलुरु से 300 किमी दूर एक स्थान पर पहुंचने की उम्मीद है। 10.30 बजे उसे पता चला कि उसने केवल 40% दूरी तय की है। अपने शेड्यूल को बनाए रखने के लिए उसे कार की गति कितनी बढ़ानी होगी?

  1.    30 km/hr (30 किमी/घंटा )
  2.    35 km/hr (35 किमी/घंटा)
  3.    40 km/hr (40 किमी/घंटा )
  4.    45 km/hr (45 किमी/घंटा)
 Discuss Question
Answer: Option A. -> 30 km/hr (30 किमी/घंटा )

To solve this question, let's break it down step by step:
The car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. This means he has a total of 4 hours to cover the distance.
At 10.30 A.M., which is 2 hours after he started, the car driver finds that he has covered only 40% of the distance. This means he has covered 40% of 300 km, which is 0.4 * 300 = 120 km.
From 8.30 A.M. to 10.30 A.M., he has covered a distance of 120 km. Therefore, he has 300 km - 120 km = 180 km left to cover in the remaining 2 hours (10.30 A.M. to 12.30 P.M.).
To determine how much he needs to increase his speed, we'll calculate the speed he needs to maintain in order to cover the remaining distance of 180 km in 2 hours.
Speed = Distance / Time
= 180 km / 2 hours
= 90 km/hour
The car driver's current speed is not sufficient to maintain his schedule, as he needs to travel at 90 km/hour to cover the remaining distance. Therefore, he needs to increase his speed by 90 km/hour - his current speed.
Since he has covered 120 km in 2 hours (from 8.30 A.M. to 10.30 A.M.), we can calculate his current speed using the formula:
Speed = Distance / Time
= 120 km / 2 hours
= 60 km/hour
Now we can determine the speed increase required:
Required Speed Increase = Desired Speed - Current Speed
= 90 km/hour - 60 km/hour
= 30 km/hour
Therefore, the car driver needs to increase the speed of the car by 30 km/hour in order to keep up with his schedule and reach the destination 300 km from Bangalore at 12.30 P.M.

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समाधान: इस प्रश्न को हल करने के लिए, आइए इसे चरण दर चरण तोड़ें:
कार चालक सुबह 8.30 बजे बेंगलुरु से निकलता है। और दोपहर 12.30 बजे बेंगलुरु से 300 किमी दूर एक स्थान पर पहुंचने की उम्मीद है। इसका मतलब है कि उसके पास दूरी तय करने के लिए कुल 4 घंटे हैं।
सुबह 10.30 बजे, जो कि चलने के 2 घंटे बाद है, कार चालक को पता चलता है कि उसने केवल 40% दूरी तय की है। इसका मतलब है कि उसने 300 किमी का 40% कवर किया है, जो 0.4 * 300 = 120 किमी है।
प्रातः 8.30 बजे से सुबह 10.30 बजे तक, उसने 120 किमी की दूरी तय की है। इसलिए, शेष 2 घंटों (सुबह 10.30 बजे से दोपहर 12.30 बजे तक) में उसे 300 किमी - 120 किमी = 180 किमी की दूरी तय करनी है।
यह निर्धारित करने के लिए कि उसे अपनी गति कितनी बढ़ाने की आवश्यकता है, हम उस गति की गणना करेंगे जिसे उसे 2 घंटे में 180 किमी की शेष दूरी तय करने के लिए बनाए रखने की आवश्यकता है।
गति = दूरी/समय
= 180 किमी/2 घंटे
= 90 किमी/घंटा
कार चालक की वर्तमान गति उसके शेड्यूल को बनाए रखने के लिए पर्याप्त नहीं है, क्योंकि उसे शेष दूरी तय करने के लिए 90 किमी/घंटा की गति से यात्रा करने की आवश्यकता है। इसलिए, उसे अपनी गति - अपनी वर्तमान गति - 90 किमी/घंटा तक बढ़ाने की आवश्यकता है।
चूँकि उसने 2 घंटे (सुबह 8.30 बजे से सुबह 10.30 बजे तक) में 120 किमी की दूरी तय की है, हम सूत्र का उपयोग करके उसकी वर्तमान गति की गणना कर सकते हैं:
गति = दूरी/समय
= 120 किमी/2 घंटे
= 60 किमी/घंटा
अब हम आवश्यक गति वृद्धि निर्धारित कर सकते हैं:
आवश्यक गति वृद्धि = वांछित गति - वर्तमान गति
= 90 किमी/घंटा - 60 किमी/घंटा
= 30 किमी/घंटा
इसलिए, कार चालक को अपने शेड्यूल के अनुसार चलने के लिए और दोपहर 12.30 बजे बेंगलुरु से 300 किमी दूर गंतव्य तक पहुंचने के लिए कार की गति 30 किमी/घंटा बढ़ानी होगी।


Question 2. You arrive at your school 5 minutes late if you walk with a speed of 4 km/h, but you arrive 10 minutes before the scheduled time if you walk with a speed of 5 km/h. The distance of your school from your house (in km) is
  1.    2
  2.    10
  3.    5
  4.    4
 Discuss Question
Answer: Option B. -> 10
Answer: (b)If the required distance be = x km, then$x/4 - x/5 = {10 + 5}/60$${5x - 4x}/20 = 1/4$$x/20 = 1/4 ⇒ x= 1/4 × 20$ = 5 km.Using Rule 10,If a man travels at the speed of $s_1$, he reaches his destination $t_1$ late while he reaches $t_2$ before when he travels at $s_2$ speed, then the distance between the two places is D = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
Question 3. Sarita and Julie start walking from the same place in the opposite directions. If Julie walks at a speed of 2$1/2$ km/hr and Sarita at a speed of 2 km/hr, in how much time will they be 18 km apart ?
  1.    4.8 hrs
  2.    5.0 hrs
  3.    4.5 hrs
  4.    4.0 hrs
 Discuss Question
Answer: Option D. -> 4.0 hrs
Answer: (d)Using Rule 12,If both objects run in opposite direction then, Relative speed = Sum of speeds.If both objects run in the same direction then, Relative speed = Difference of Speeds.Time taken in meeting = $\text"Distance between them"/\text"Relative Speed"$
Question 4. A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/ hr. If he takes 5 hours in going and coming, the distance between his house and school is :
  1.    6.5 km
  2.    5.5 km
  3.    5 km
  4.    6 km
 Discuss Question
Answer: Option D. -> 6 km
Answer: (d)Let the required distance be x km. Then,$x/3 + x/2$ = 5${2x + 3x}/6$ = 55x = 6 × 5x = ${6 × 5}/5$ = 6 kmUsing Rule 5,Here, x = 3, y = 2Average Speed = ${2 × x × y}/{x + y}$= ${2 × 3 × 2}/{3 + 2} = 12/5$ km/hrTotal distance = $12/5 × 5$ = 12kmRequired distance = $12/2$ = 6 km
Question 5. A speed of 30.6 km/.hr is the same as
  1.    15.5 m/sec.
  2.    12 m/sec.
  3.    l0 m/sec.
  4.    8.5 m/sec.
 Discuss Question
Answer: Option D. -> 8.5 m/sec.
Answer: (d)30.6 kmph = $(30.6 × 5/18)$ m/sec.= 8.5 m/sec
Question 6. A train is travelling at the rate of 45km/hr. How many seconds it will take to cover a distance of $4/5$ km ?
  1.    120 sec.
  2.    90 sec.
  3.    64 sec.
  4.    36 sec.
 Discuss Question
Answer: Option B. -> 90 sec.
Answer: (b)Using Rule 1,Distance = Speed × TimeSpeed = $\text"Distance"/\text"Time"$ , Time = $\text"Distance"/\text"Speed"$1 m/s = $18/5$ km/h, 1 km/h = $5/18$ m/s
Question 7. A man rides at the rate of 18 km/ hr, but stops for 6 mins. to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is
  1.    6 hrs. 24 min.
  2.    6 hrs. 18 min.
  3.    6 hrs. 12 min.
  4.    6 hrs.
 Discuss Question
Answer: Option B. -> 6 hrs. 18 min.
Answer: (b)90 km = 12 × 7km + 6 km.To cover 7 km total time taken = $7/18$ hours + 6 min. = $88/3$ min.So, (12 × 7 km) would be covered in $(12 × 88/3)$ min.and remaining 6km is $6/18$ hrs or 20 min.Total time = $1056/3$ + 20= $1116/{3 × 60}$ hours = 6$1/5$ hours= 6 hours 12 minutes.
Question 8. A and B travel the same distance at speed of 9 km/hr and 10 km/ hr respectively. If A takes 36 minutes more than B, the distance travelled by each is
  1.    66 km
  2.    60 km
  3.    54 km
  4.    48 km
 Discuss Question
Answer: Option B. -> 60 km
Answer: (b)Let the distance between A and B be x km, then$x/9 - x/10 = 36/60 = 3/5$$x/90 = 3/5$$x = 3/5 × 90$ = 54 km.Using Rule 9,Here, $S_1 = 9, t_1 = x, S_2 = 10, t_2 = x - 36/60$$S_1t_ 1 = S_2t_ 2$$9 × x = 10(x - 36/60)$9x = 10x - 6 = 6Distance travelled = 9 × 6 = 54 km
Question 9. A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was
  1.    15 km
  2.    20 km
  3.    30 km
  4.    25 km
 Discuss Question
Answer: Option C. -> 30 km
Answer: (c)Let the distance be x km.Total time = 5 hours 48 minutes= $5 + 48/60 = (5 + 4/5)$ hours= $29/5$ hours$x/25 + x/4 = 29/5$${4x + 25x}/100 = 29/5$5 × 29x = 29 × 100$x = {29 × 100}/{5 × 29}$ = 20 km. Using Rule 5,If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$
Question 10. A man travelled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km per hour and partly on bicycle at 16km per hour. The distance travelled on the foot is
  1.    44 km
  2.    36 km
  3.    48 km
  4.    32 km
 Discuss Question
Answer: Option D. -> 32 km
Answer: (d)Journey on foot=x kmJourney on cycle = (80 –x)km$x/8 + {80 - x}/16 = 7$${2x + 80 - x}/16 = 7$x + 80 = 16 × 7 = 112x= 112 - 80 = 32 km. Using Rule 13,Let a man take 't' hours to travel 'x' km. If he travels some distance on foot with the speed u km/h and remaining distance by cycle with the speed v km/h,then time taken to travel on foot.Time = ${(vt - x)}/{(v - u)}$Distance travelled on foot = Time × u

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