Question
A person started his journey in the morning. At 11 a.m. he covered $3/8$ of the journey and on the same day at 4.30 p.m. he covered $5/6$ of the journey. He started his journey at
Answer: Option A
Answer: (a)Difference of time= 4.30 p.m - 11.a.m.= $5{1}/2$ hours $11/2$ hoursDistance covered in $11/2$ hrs= $5/6 - 3/8 = {20 - 9}/24 = 11/24$ partSince, $11/24$ part of the journey is covered in $11/2$ hours$3/8$ part of the journey is covered in= $11/2 × 24/11 × 3/8$= $9/2$ hours = 4$1/2$ hours.Clearly the person started at 6.30 a.m.
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Answer: (a)Difference of time= 4.30 p.m - 11.a.m.= $5{1}/2$ hours $11/2$ hoursDistance covered in $11/2$ hrs= $5/6 - 3/8 = {20 - 9}/24 = 11/24$ partSince, $11/24$ part of the journey is covered in $11/2$ hours$3/8$ part of the journey is covered in= $11/2 × 24/11 × 3/8$= $9/2$ hours = 4$1/2$ hours.Clearly the person started at 6.30 a.m.
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