Quantitative Aptitude
SPEED TIME AND DISTANCE MCQs
Time & Distance
Total Questions : 422
| Page 2 of 43 pages
Answer: Option A. -> 12
Answer: (a)Since, 1 m/sec = $18/5$ kmph$10/3$ m/sec= $18/5 × 10/3$ = 12 kmph
Answer: (a)Since, 1 m/sec = $18/5$ kmph$10/3$ m/sec= $18/5 × 10/3$ = 12 kmph
Answer: Option B. -> 12.5
Answer: (b)Using Rule 1,Speed = $\text"Distance"/\text"Time" = 250/75$= $10/3$ m/sec = $10/3 × 18/5$ km/hr[Since, 1 m/s = $18/5$ km/hr]= 2 × 6 km/hr. = 12 km/hr.
Answer: (b)Using Rule 1,Speed = $\text"Distance"/\text"Time" = 250/75$= $10/3$ m/sec = $10/3 × 18/5$ km/hr[Since, 1 m/s = $18/5$ km/hr]= 2 × 6 km/hr. = 12 km/hr.
Answer: Option C. -> 6.67 km/hr
Answer: (c)Using Rule 1,Remaining time= $2/5 × 15 = 6$ hoursRequired speed= $60/6$ = 10 kmph
Answer: (c)Using Rule 1,Remaining time= $2/5 × 15 = 6$ hoursRequired speed= $60/6$ = 10 kmph
Answer: Option B. -> $b/a$ hours
Answer: (b)Using Rule 1,Man's speed = $\text"Distance"/ \text"Time"$= $a/b$ kmph = ${1000a}/b$ m/hourTime taken in walking 200 metre= $200/{{1000a}/b} =b/{5a}$ hours
Answer: (b)Using Rule 1,Man's speed = $\text"Distance"/ \text"Time"$= $a/b$ kmph = ${1000a}/b$ m/hourTime taken in walking 200 metre= $200/{{1000a}/b} =b/{5a}$ hours
Answer: Option A. -> 720 km./hr.
Answer: (a)Using Rule 1,Let the required speed is x km/ hrThen, $240 × 5 = 5/3 × x$x = 720 km/hr.
Answer: (a)Using Rule 1,Let the required speed is x km/ hrThen, $240 × 5 = 5/3 × x$x = 720 km/hr.
Answer: Option A. -> 50
Answer: (a)Using Rule 1,Speed = 180 kmph= ${180 × 5}/18$ m/sec = 50 m/sec[Since, 1 km/hr = $5/18$ m/s]
Answer: (a)Using Rule 1,Speed = 180 kmph= ${180 × 5}/18$ m/sec = 50 m/sec[Since, 1 km/hr = $5/18$ m/s]
Answer: Option D. -> 100 m
Answer: (d)Using Rule 1,Speed of bus = 72 kmph= $({72 × 5}/18)$ metre/second= 20 metre/second∴ Required distance= 20 × 5 = 100 metre
Answer: (d)Using Rule 1,Speed of bus = 72 kmph= $({72 × 5}/18)$ metre/second= 20 metre/second∴ Required distance= 20 × 5 = 100 metre
Answer: Option A. -> 36
Answer: (a)Using Rule 1,Speed of car = 10 m/sec.Required speed in kmph=${10 × 18}/5 = 36$ km/hr
Answer: (a)Using Rule 1,Speed of car = 10 m/sec.Required speed in kmph=${10 × 18}/5 = 36$ km/hr
Answer: Option B. -> 13 minutes
Answer: (b)Using Rule 1,Speed of train = $\text"Distance"/ \text"Time"$= $10/{12/60}$ kmph = ${10 × 60}/12 = 50$ kmphNew speed = 45 kmphRequired time = $10/45$ hour= $2/9 × 60$ minutes = $40/3$ minutes= 13 minutes 20 seconds
Answer: (b)Using Rule 1,Speed of train = $\text"Distance"/ \text"Time"$= $10/{12/60}$ kmph = ${10 × 60}/12 = 50$ kmphNew speed = 45 kmphRequired time = $10/45$ hour= $2/9 × 60$ minutes = $40/3$ minutes= 13 minutes 20 seconds
Answer: Option A. -> 1250
Answer: (a)Using Rule 1,Speed of the man = 5km/hr= $5 × 1000/60$ m/min = $250/3$ m/minTime taken to cross the bridge= 15 minutesLength of the bridge= speed × time= $250/3 × 15$m = 1250m
Answer: (a)Using Rule 1,Speed of the man = 5km/hr= $5 × 1000/60$ m/min = $250/3$ m/minTime taken to cross the bridge= 15 minutesLength of the bridge= speed × time= $250/3 × 15$m = 1250m