Question
A car travels 50% faster than a bike. Both start at the same time from A to B. The car reaches 25 minutes earlier than the bike. If the distance from A to B is 100 km, find the speed of the bike.
Answer: Option C
LET THE SPEED OF THE BIKE BE X KMPH. THEN THE SPEED OF THE CAR WILL BE 3X/2 KMPH. TIME TAKEN BY THE BIKE
T1 = 100/X TIME TAKEN BY THE BIKE
T2 = 100/(3X/2) T1 – T2 = 25/60 (100/X) – (100/(3X/2)) = 5/12 SOLVING THE EQUATION, X = 80 KMPH
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LET THE SPEED OF THE BIKE BE X KMPH. THEN THE SPEED OF THE CAR WILL BE 3X/2 KMPH. TIME TAKEN BY THE BIKE
T1 = 100/X TIME TAKEN BY THE BIKE
T2 = 100/(3X/2) T1 – T2 = 25/60 (100/X) – (100/(3X/2)) = 5/12 SOLVING THE EQUATION, X = 80 KMPH
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