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12th Grade > Physics

KINETIC THEORY OF GASES MCQs

Total Questions : 24 | Page 2 of 3 pages
Question 11. A system which exchanges both matter & energy with the surrounding is called a closed system.
  1.    True
  2.    False
  3.    Closed system
  4.    None
 Discuss Question
Answer: Option B. -> False
:
B
A system which exchanges both matter & energy with the surroundings is called an open system by definition.
Open system -matter and energy both can be transferred.
Closed system - Only energy can be transferred.
Isolated - Neither energy nor matter can be transferred.
Question 12. Find the value of ΔU.
Find The Value Of ΔU.
  1.    +20 J
  2.    -80 J
  3.    +80 J
  4.    -20 J
 Discuss Question
Answer: Option B. -> -80 J
:
B
Take a minute and try to get this on your own. Then move on the next video for the explanation.
Question 13. Fundamental properties which determine the state of a system are referred to as state variables.
  1.    True
  2.    False
  3.    Closed system
  4.    None
 Discuss Question
Answer: Option A. -> True
:
A
Fundamental properties which determine the state of a system are referred to as state variables or state functions or thermodynamic parameters. The change in the state properties depends only on the initial and final states of the system, but is independent of the manner in which the change has been brought about. In other words, the state properties do ont depend upon the path taken.
Question 14. The Bat Life: What can be said with 100% confidence about the temperatures at point P1 and P2?
  1.    TP1=TP2
  2.    TP1 > TP2
  3.    TP1 < TP2
  4.    TP1≠TP2.
 Discuss Question
Answer: Option D. -> TP1≠TP2.
:
D
Just like a single macroscopic pressure being undefined for a gas which is not in equilibrium, a single macroscopic temperature is also undefined. So the temperature at P1andP2 need not necessarily be the same, and most likely wouldn't be the same.
Question 15. An air bubble doubles its radius on raising from the bottom of water reservoir to be the surface of water in it. If the atmospheric pressure is equal to 10 m of water, the height of water in the reservoir is  An Air Bubble Doubles Its Radius On Raising From The Bottom ...
  1.    10 m
  2.    20 m
  3.    70 m
  4.    80 m
 Discuss Question
Answer: Option C. -> 70 m
:
C
Accoding to Boyle's law (P1V1)bottom = (P2V2)top
(10 + h) × 43πr13 = 10 × 43πr23 but r2=2r1
(10 + h)r13 = 10 × 8 r13 10 + h = 80 h = 70 m
Question 16. The energy of a gas per litre is 300 joules, then its pressure will be
  1.    3 ×105Nm2
  2.    6 ×105Nm2
  3.    105Nm2
  4.    2 ×105Nm2
 Discuss Question
Answer: Option D. -> 2 ×105Nm2
:
D
Energy = 300 J/litre = 300 ×103J/m3
P= 23E=2×300×1033 = 2 ×105N/m2
Question 17. A cylinder of fixed capacity 44.8 litre. contains a monatomic gas at standard temperature and pressure. The amount of heat required to increse the temperature of cylinder by 10C will be. (R = universal gas constant) 
  1.    R
  2.    10R
  3.    20R
  4.    30R
 Discuss Question
Answer: Option D. -> 30R
:
D
As we know 1 mol of any ideal gas at STP occupies a volume of 22.4 liters.
Hence number of moles of gas μ=44.822.4 = 2
Since the volume of cylinder is fixed,
Hence (Q)V = μ(CV)T=2×32R×10 = 30R((CV)mono=3R2))
Question 18. An enclosure of volume V contains a mixture of 8 g of oxygen, 14 g of nitrogen and 22 g of carbon- dioxide at absolute temperature T. The pressure of the mixture of gases is (R is universal gas constant)
  1.    RTV
  2.    3RT2V
  3.    5RT4V
  4.    7RT5V
 Discuss Question
Answer: Option C. -> 5RT4V
:
C
The pressure exerted by a gas is given by
P=nRTV
= massmolecularweight×RTV
Pressure exerted by oxygen P1=832RTV=14RTV
Pressure exerted by oxygen P2=1428RTV=12RTV
Pressure exerted by carbon dioxide
P3=2244RTV=12RTV
From Dalton's law of partial pressures, the total pressure exerted by the mixture is given by
P=P1+P2+P3
=14RTV+12RTV+12RTV
= 5RT4V,
which is choice (c)
Question 19. If pressure of CO2 (real gas) in a container is given by P = RT2Vba4V2 then mass of the gas in container is  
  1.    11 gm
  2.    22 gm
  3.    33 gm
  4.    44 gm
 Discuss Question
Answer: Option B. -> 22 gm
:
B
Vander wal's gas equation for μ mole of real gas
(P + μ2αV2)(V - μb) = μRT P = μRTVμbμ2V2
on comparing the given equation with this standard equation we get μ=12. Hence μ = mM mass of gas
m = μM = 12×44 = 22gm
Question 20. The ratio of two specific heats CpCv of CO is 
  1.    1.33 
  2.    1.40
  3.    1.29
  4.    1.66
 Discuss Question
Answer: Option B. -> 1.40
:
B
CO is diatomic gas, for diatomic gas
Cp=72R and Cv=52Rγ=CpCv=7R25R2 = 1.4

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