Question
An air bubble doubles its radius on raising from the bottom of water reservoir to be the surface of water in it. If the atmospheric pressure is equal to 10 m of water, the height of water in the reservoir is 
Answer: Option C
:
C
Accoding to Boyle's law (P1V1)bottom = (P2V2)top
(10 + h) × 43πr13 = 10 × 43πr23 but r2=2r1
∴ (10 + h)r13 = 10 × 8 r13 ∴ 10 + h = 80 ∴ h = 70 m
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:
C
Accoding to Boyle's law (P1V1)bottom = (P2V2)top
(10 + h) × 43πr13 = 10 × 43πr23 but r2=2r1
∴ (10 + h)r13 = 10 × 8 r13 ∴ 10 + h = 80 ∴ h = 70 m
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