Question
If pressure of CO2 (real gas) in a container is given by P = RT2V−b−a4V2 then mass of the gas in container is
Answer: Option B
:
B
Vander wal's gas equation for μ mole of real gas
(P + μ2αV2)(V - μb) = μRT ⇒ P = μRTV−μb−μ2V2
on comparing the given equation with this standard equation we get μ=12. Hence μ = mM⇒ mass of gas
m = μM = 12×44 = 22gm
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:
B
Vander wal's gas equation for μ mole of real gas
(P + μ2αV2)(V - μb) = μRT ⇒ P = μRTV−μb−μ2V2
on comparing the given equation with this standard equation we get μ=12. Hence μ = mM⇒ mass of gas
m = μM = 12×44 = 22gm
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