Reasoning Aptitude
DATA SUFFICIENCY MCQs
Total Questions : 590
| Page 57 of 59 pages
Answer: Option E. -> Both I and II are sufficient
As given in I and II, we have: G = V = K, V + K + A = 32 and A = V + K.
Putting V + K = A in V + K + A = 32, we have: 2A = 32 or A = 16.
Thus, V + K = 16 and V = K. So, V = K = 8. Thus, G = 8.
As given in I and II, we have: G = V = K, V + K + A = 32 and A = V + K.
Putting V + K = A in V + K + A = 32, we have: 2A = 32 or A = 16.
Thus, V + K = 16 and V = K. So, V = K = 8. Thus, G = 8.
Answer: Option D. -> Neither I nor II is sufficient
From I, we have: R>Q, R>T, S>R i.e. S>R>Q>T or S>R>T>Q.
From II, S is not the heaviest. So, P is the heaviest. Thus, we have: P > S > R > Q > T or P > S > R > T > Q. Hence, either T or Q is the lightest.
From I, we have: R>Q, R>T, S>R i.e. S>R>Q>T or S>R>T>Q.
From II, S is not the heaviest. So, P is the heaviest. Thus, we have: P > S > R > Q > T or P > S > R > T > Q. Hence, either T or Q is the lightest.
Answer: Option E. -> Both I and II are sufficient
From I, we have the order : A, M, T.
From II, we have the order: T, R, S.
Combining the above two, we get the order: A, M, T, R, S.
Thus, Sonal came last for the programme.
From I, we have the order : A, M, T.
From II, we have the order: T, R, S.
Combining the above two, we get the order: A, M, T, R, S.
Thus, Sonal came last for the programme.
Answer: Option D. -> Neither I nor II is sufficient
From I, we have: S = T - 20.
From II, we have: V = T + 30.
Thus, from both I and II, we have: V + S = (T + 30) + (T - 20) = (2 T + 10).
So, to get the required amount, we need to know the amount that Tarun has.
From I, we have: S = T - 20.
From II, we have: V = T + 30.
Thus, from both I and II, we have: V + S = (T + 30) + (T - 20) = (2 T + 10).
So, to get the required amount, we need to know the amount that Tarun has.
Answer: Option C. -> Either I or II is sufficient
'59' means 'injurious habit' and '157' means 'stop bad habit' (from I). Thus, the common code number '5' stands for common word 'habit'. So, '9' represents 'injurious'. Hence, I is sufficient.
Also, '59' means 'injurious habit' and '839' means 'smoking is injurious'. Thus, the common code number '9' stands for common word 'injurious'. So, '5' represents 'habit'. Thus, II is also sufficient.,
'59' means 'injurious habit' and '157' means 'stop bad habit' (from I). Thus, the common code number '5' stands for common word 'habit'. So, '9' represents 'injurious'. Hence, I is sufficient.
Also, '59' means 'injurious habit' and '839' means 'smoking is injurious'. Thus, the common code number '9' stands for common word 'injurious'. So, '5' represents 'habit'. Thus, II is also sufficient.,
Answer: Option E. -> Both I and II are sufficient
Clearly, the birthday of Gautam's mother can be found out from II and then Gautam's birthday can be determined using the fact given in I.
Clearly, the birthday of Gautam's mother can be found out from II and then Gautam's birthday can be determined using the fact given in I.
Answer: Option E. -> Both I and II are sufficient
In I and II, the common word is 'is' and the common code word is 'ke'. So, 'ke' is the code for 'is'.
In I and II, the common word is 'is' and the common code word is 'ke'. So, 'ke' is the code for 'is'.
Question 568. Question : Among A, B, C, D and E, who is in the middle while standing in a row ?
Statements :
I. C, who is third to the left of D, is to the immediate right of A and second to the left of E.
II. C is second to the left of E, who is not at any of the ends and who is third to the right of A. D is at one of the ends.
Statements :
I. C, who is third to the left of D, is to the immediate right of A and second to the left of E.
II. C is second to the left of E, who is not at any of the ends and who is third to the right of A. D is at one of the ends.
Answer: Option C. -> Either I or II is sufficient
From each one of I and II, we get the order : A, C, B, E, D. Clearly, B is in the middle.
From each one of I and II, we get the order : A, C, B, E, D. Clearly, B is in the middle.
Answer: Option A. -> I alone is sufficient while II alone is not sufficient
In the two statements given in I, the common words are 'But', 'None', 'And' and the common code words are 'Ne', 'Pa', ,'Lo'. So, 'Ne', 'Pa' and 'Lo' are codes for 'But', 'None' and 'And'. Thus, in the first statement, 'Sic' is the code for 'No'.
In the two statements given in I, the common words are 'But', 'None', 'And' and the common code words are 'Ne', 'Pa', ,'Lo'. So, 'Ne', 'Pa' and 'Lo' are codes for 'But', 'None' and 'And'. Thus, in the first statement, 'Sic' is the code for 'No'.
Answer: Option A. -> I alone is sufficient while II alone is not sufficient
From I, we conclude that since none of A and D is the heaviest and each one of B, E and F is lighter than both A and D, so C is the heaviest.
From I, we conclude that since none of A and D is the heaviest and each one of B, E and F is lighter than both A and D, so C is the heaviest.
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