Answer: Option A. -> 38.5
:
A
When you arrange the datain ascending order, you get:
6 9 12 19 23 34 43 54 56 69 74 87
If number of observations is odd then median is the$\left(\frac{n}{2}\right)$th term
Ifit is even then median is the mean of the $\left(\frac{n}{2}\right)$th and($\frac{n}{2})+1)$ th term.
Here the numberof observations is 12 - even,
Therefore, the median will be an average of $6^{th}$and $7^{th}$observation.
So, Median=$\frac{34+43}{2}$=$\frac{77}{2}$=38.5.

Answer: Option C. -> Abibas
:
C
Average star rating = $\frac{\text{Total number of stars given by people}}{\text{Total number of people who gave the rating}}$.
For Ruma,average star rating = $\frac{180\times 5+104\times 4+95\times 3+12\times 2+11\times 1}{180+104+95+12+11}$ = 4.07
For Peebok,average star rating = $\frac{150\times 5+110\times 4+87\times 3+22\times 2+23\times 1}{150+110+87+22+23}$ = 3.87
For Abibas,average star rating = $\frac{234\times 5+98\times 4+88\times 3+16\times 2+18\times 1}{234+98+88+16+18}$ = 4.13
4.13> 4.07> 3.87
So,Abibas has the highest rating.

Answer: Option B. -> 1-c  , 2-d , 3-b , 4-e , 5-a    
:
B
As seen from the graph,
the quantity of apples sold = 5 kg,
the quantity of mangoessold= 15 kg,
the quantity of bananas sold = 20 kg,
the quantity of pineapples sold = 10 kg and
the quantity of papayas sold = 25 kg.
Thus, 1 - c,2 - d,3 - b,4 - e,5 - a is correct.

:
In the 1000 observations, 9 will be the mode.
In 1020 observations, frequency of 9 = 13 + 1 = 14
In 1020 observations, frequency of 13 = 19
So, mode of the observations = 13.

Answer: Option C. -> 6.5
:
C
Arranged data set is:
1 4 6 6 9 12 13 19 25 33 45 56
Median: The middle most value after arranging the given data.
Here, the number of observations is 12, which is an even number.So, we take the average of thetwo observations in the middle to find the value of median.
Median=$\frac{12+13}{2}$=12.5. (Mean of the $6^{th}$ and$7^{th}$ observation)
Mode:Theobservation that occurs most often in the data set.
We can find 6 two times in the data set. This is the most repeated value in the data set. The value of the mode is 6.
i.e., Mode=6.
Difference betweenmedian and mode of the given data set=12.5-6=6.5.

Answer: Option B. -> the data which lies in the middle of an organised data set.
:
B
Median is defined as the data which lies in the middle of an organised data set. Median refers to the value which lies in the middle of the data (when arranged in an increasing or decreasing order) with half of the observations above it and the other half below it.

Answer: Option C. -> 85
:
C
Average $=\frac{\text{Total marks}}{\text{Total number of student}}$
$65=\frac{3080+\text{Marks scoredbyArjun}+\text{Marksscored by Karan}}{50}$.
Since marks scored by Arjun =Marks scored by Karan
Marks scored by Arjun +Marks scored by Karan =2 $\times$ Marks scored by Arjun.
So, 65 $\times$ 50 = 3080 + 2 $\times$ Marks scored by Arjun.
So, marks scored by Arjun $=\frac{3250-3080}{2}=\frac{170}{2}=85$ marks.

Answer: Option B. -> Mode   
:
B
Mean and Range may or may not be equal to any of the observations from the data set. Median is one of the observations if the number of observations is odd. If it's even, median also won't be equal to one of the observations. But mode is always equal to one of the observations.

Answer: Option C. -> Deepthi
:
C
We know that,
$Average=\frac{Sumofallobservations}{Totalnumberofobservations}$​​
Average marks=$\frac{79+81+68+85+62+77+73+94+81+80}{10}$=$\frac{780}{10}$=78.
Students who scored less marks than the average, won't be promoted to section A. So, from the given options, only Deepthi has lesser marks than 78.

:
Drawing double bar graph: 2 Marks
Each part: 0.5 Marks
$\Rightarrow$ Data represented by double bar graph is as follows:

(i) Jammu has the largest difference in temperature i.e., Maximum temperature = ${41}^{\circ }C$and Minimum temperature = ${26}^{\circ }C$
$\therefore$ Difference = ${41}^{\circ }C–{26}^{\circ }C={15}^{\circ }C$
(ii) Jammu is the hottest city as the maximum temperature is the highest among all the given cities and Bangalore is the coldest city because theminimum temperature there is lowest among all the given cities.
(iii) Maximum temperature of Bangalore = ${28}^{\circ }C$
Minimum temperature of two cities whose minimum temperature is higher than the maximum temperature of Bangalore are Ahmedabad and Jaipur = ${29}^{\circ }C$
(iv) Mumbai has the least difference in temperature i.e., Maximum temperature = ${32}^{\circ }C$ and Minimum temperature = ${27}^{\circ }C$.
$\therefore$ Difference = ${32}^{\circ }C–{27}^{\circ }C=5^{\circ }C$