This is the observation from the bar graph.

Shubh’s total = 85+75+95 = 255

Aman’s total = 85 + 95 + 75 = 255

Anurag’s total = 90 + 80 + 85 = 255

Since total marks are same for all the three, average will be same too. So, there is nobody with the highest average.

Range is the difference between the observation having the maximum value and the observation having the minimum value.

In the above case, all the observations are same. So, the range is 50 - 50 = 0.

Organised data is easier to analyse and interpret. In data handling, the data is arranged either in ascending or descending order to easily find out the required data from the data set.

The probability of getting head and tail is same i.e. $\frac{1}{2}$ . But we can't be sure anyway that we will get head for a certain number of times and tail for a certain number of times.

The probability of getting a head or a tail while tossing a coin is $\frac{1}{2}$ that is equal for both the cases.

Data set 1 is in ascending order, whereas data set 2 is in descending order. So, both of them are organized. But we can see that data set 3 is random. Hence, it is an unorganised data set.

The performance of a football player doesn't depend on his name or nationality. Performance solely depends on  stamina and height. So, the data sets which will help us take a better decision are height and stamina of the players

Average star rating = $\frac{\text{Total number of stars given by people}}{\text{Total number of people who gave the rating}}$.

For Ruma,average star rating = $\frac{180\times 5+104\times 4+95\times 3+12\times 2+11\times 1}{180+104+95+12+11}$ = 4.07

For Peebok,average star rating = $\frac{150\times 5+110\times 4+87\times 3+22\times 2+23\times 1}{150+110+87+22+23}$ = 3.87

For Abibas,average star rating = $\frac{234\times 5+98\times 4+88\times 3+16\times 2+18\times 1}{234+98+88+16+18}$ = 4.13
4.13 > 4.07 > 3.87

So, Abibas has the highest rating.

When you arrange the data in ascending order, you get:

 6          9          12        19        23        34        43        54        56        69        74        87

If number of observations is odd then median is the  $\left(\frac{n}{2}\right)$th term

If it is even then median is the mean of the  $\left(\frac{n}{2}\right)$th and ($\frac{n}{2})+1)$ th term.

Here the number of observations is 12 - even,

Therefore, the median will be an average of $6^{th}$ and $7^{th}$ observation.

 So, Median=$\frac{34+43}{2}$=$\frac{77}{2}$=38.5.

$Mean=\frac{Sumofallobservations}{Totalnumberofobservations}$​​
$Mean=\frac{2+4+3+1+2}{5}=\frac{12}{5}=$2.4
$\text{Range = highest observation - lowest observation}$

$Range=4-1=$3

$\text{Difference between range and mean}$
             $=3-2.4=0.6$