Data Handling(7th Grade > Mathematics ) Questions and answers for exam Preparation

7th Grade > Mathematics

DATA HANDLING MCQs

Total Questions : 114 | Page 1 of 12 pages

Question 1. Find the range of following set of integers:
-2 , 5 , 12, -10, 0, -9 , -13, 1, 4 , 2 , 9, -8

25
-1
-19
19

Discuss Question

Answer: Option A. -> 25
:
A
The difference between the highest and lowest observations is called range.
Largest integer

12.
Smallest integer

-13.
Range

12-(-13)

25.

Question 2. A mathematics teacher wanted to see, whether the new technique of teaching she applied after the quarterly test was effective or not. She took the scores of the 5 weak children in the quarterly test (out of 25) and in the half-yearly test (out of 25): [4 MARKS]

\begin{matrix} S t u d e n t s & A s h i s h & A r u n & K a v i s h & M a y a & R i t a Q u a r t e r l y & 10 & 15 & 12 & 20 & 9 H a l f y e a r l y & 15 & 18 & 16 & 21 & 15 \end{matrix}

Draw a double bar graph. Using the graph answer the following questions.
(i) Is the new technique of teaching effective?
(ii) Who has benefitted more from the new technique?

Discuss Question

:
Double bar graph: 2 Marks
Each part: 1 Mark
(i) Double bar graph :
Scale: y axis - 1 cm = 5 units

A Mathematics Teacher Wanted To See, Whether The New Techniq...

(i) Every student scored more in the half-yearly than the quarterly.

\Rightarrow

Newtechnique of teaching is effective.
(ii) The difference of marks scored by Rita in quarterly and half yearly is maximum.

\Rightarrow

Rita has benefitted more from thenew technique.

Question 3. Find the mean of first five multiples of 5. [2 MARKS]

Discuss Question

:
Formula: 1 Mark
Solution:1 Mark
Firstfive multiples of 5 are 5,10,15, 20 and 25.

Mean = \frac{Sum of all observation}{Total number of observation}

Mean = \frac{5 + 10 + 15 + 20 + 25}{5} = 15

Question 4. Calculate the Mean, Median, Mode of the following data: 5,10,10,12, 13
Are these three equal? [3 MARKS]

Discuss Question

:
Mean, Median, Mode: Each 1 Mark

M e a n = \frac{Sum of all observation}{Total number of observation}

\Rightarrow Mean = \frac{5 + 10 + 10 + 12 + 13}{5} = \frac{50}{5} = 10

Median is the middle most observationof the given observations.

\Rightarrow Median = 10

The mode is the most repeated observationof the given observations.

\Rightarrow Mode = 10

Hence, for this observation, Mean, Median, Mode are equal.

Question 5. (a) The profits of a soft drink firm during certain months of a year are given alongside. Draw a Bar graph. [4 MARKS]

\begin{matrix} M o n t h s & P r o f i t s (i n t h o u s a n d s) J a n u a r y & 2.4 F e b r u a r y & 1.8 M a r c h & 3.0 A p r i l & 4.0 M a y & 5.2 J u n e & 4.0 J u l y & 2.0 \end{matrix}

(b) The following bar graph shows the number of men and women visiting a sports complex. Can you spot the day when the number of men was equal to the number of women and on which day is the number of women 20 more than the number of men?

(a) The Profits Of A Soft Drink Firm During Certain Months O...

Discuss Question

:
(a) 2 Marks
(b) 2 Marks
Scale : x - axis - Months
y - axis - Profits in thousands - 1 cm = 1 Thousand

(b)

Here, the height of the bar graph gives us the number of men and women. For Thursday, the height of both the graphs is same. So, on Thursday,the number of men was equal to the number of women.
On Monday the number of women is 20 more than the number of men. (No. of men = 40 ,No. of women = 60)

Question 6. Following table shows the points of each player scored in four games:

\begin{matrix} P l a y e r & G a m e & G a m e & G a m e & G a m e 1 & 2 & 3 & 4 S u r a j & 10 & 16 & 14 & 10 A b h i j i t & 8 & 0 & 4 & 6 H a r s h i t h & 13 & D i d n o t & 11 & 8 P l a y \end{matrix}

Based on the above table answer the following questions:
(i) Find the mean to determine Suraj's average number of points scored per game.
(ii) To find the mean number of points per game of Harshith, would you divide the total points by 3 or by 4? Why?
(iii) Abhijit played in all the four games. How would you find the mean?
(iv) Who is the best performer? [4 MARKS]

Discuss Question

:
Solution: 1 Mark each
(i) Suraj's average number of points.

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{10 + 16 + 14 + 10}{4} = \frac{50}{4}

\Rightarrow M e a n = 12.5

(ii)To find the mean number of points per game of Harshith, mean should be divided by 3 because he played in only 3 games.

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{13 + 11 + 8}{3} = \frac{32}{3}

\Rightarrow M e a n = 10.66

(iii) For Abhijit's game mean is:

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{8 + 0 + 4 + 6}{4} = \frac{18}{4}

\Rightarrow M e a n = 4.5

(iv) Comparing everybody's mean score, Suraj has highest mean.

\Rightarrow

Suraj is best performer.

Question 7. Sale of English and Hindi books in the years 1995, 1996, 1997 and 1998 are given below:

\begin{matrix} Y e a r s & 1995 & 1996 & 1997 & 1998 E n g l i s h & 350 & 400 & 450 & 620 H i n d i & 500 & 525 & 600 & 650 \end{matrix}

Draw a double bar graph and answer the following questions:
(a) In which year was the difference in the sale of the two language books least?
(b) Can you say that the demand for english books increased? Justify. [4 MARKS]

Discuss Question

:
Double Bar graph: 2 Marks
Answers:1 Mark each
Double bar graph:

Sale Of English And Hindi Books In The Years 1995, 1996, 199...

(a) In the year 1998, the difference in the sale of the two language books was least.
(b) Yes, the demand for English books increased. From the graph, it is evident that the difference in the demand for English books from 1995 to 1998 is 620 - 350 = 270.
Whereas for Hindi books the difference is 650 - 500 = 150.
Comparatively, the demand for English books increased.

Question 8. Find the mode of 2, 14, 16, 12, 14, 14, 16, 14, 10, 14, 18, 14. [1 MARK]

Discuss Question

:
Given Data is: 2, 14, 16, 12, 14, 14, 16, 14, 10, 14, 18, 14.
Arranging the observations in the ascending order.
2, 10, 12, 14, 14, 14, 14, 14, 14, 16, 16, 18.
Clearly, the most repeated observation is 14.

\Rightarrow

14 is mode.

Question 9. You have a 8 faced die having numbers from 1 to 8 on its 8 faces. What would be the probability of getting 8 on throwing it?

Discuss Question

Answer: Option C. -> 18
:
C
If there are 6 faces, the probability of getting one of 6 digits is

\frac{1}{6}

. So, in the case of 8 faces, probability of getting any of the 8 numbers must be

\frac{1}{8}

.Hence, theprobability of getting 8 on throwing it is

\frac{1}{8}

Question 10. Find the median of the following data set.
12 65 3 8 23 64 19 53 0 24 57 15 39

Discuss Question

Answer: Option B. -> 23
:
B
After arranging the data in ascending order, we get:
0, 3, 8, 12, 15, 19, 23, 24, 39, 53, 57,64, 65.
Here, n = 13 = Odd