Exams > Cat > Quantitaitve Aptitude
BASIC ARITHMETIC MCQs
Total Questions : 150
| Page 7 of 15 pages
Answer: Option C. -> 150
:
C
Actual =60%of250=60100×250=604×10=6004=150
:
C
Actual =60%of250=60100×250=604×10=6004=150
Answer: Option D. -> 6427
:
D
Let the sum be P and the interest rate be r.
Then after ‘n’ years A=P(1+r100)n=PRnwhereR=1+r100
Now, 17820=PR3,49410=PR6
R3=4941017820
So, P=17820×1782049410 =Rs.6427
:
D
Let the sum be P and the interest rate be r.
Then after ‘n’ years A=P(1+r100)n=PRnwhereR=1+r100
Now, 17820=PR3,49410=PR6
R3=4941017820
So, P=17820×1782049410 =Rs.6427
Answer: Option C. -> Rs. 150
:
C
Let the required price be Rs. x
Dividend = 9% of Rs. 200 = Rs. 18
0.12x = 18 ⇒x = Rs. 150
Hence option (c)
:
C
Let the required price be Rs. x
Dividend = 9% of Rs. 200 = Rs. 18
0.12x = 18 ⇒x = Rs. 150
Hence option (c)
Answer: Option D. -> No profit, No loss
:
D
20% of 40,000 = 8000.
Profit = loss = 8000.
Hence, No Profit, No loss; Option (d).
:
D
20% of 40,000 = 8000.
Profit = loss = 8000.
Hence, No Profit, No loss; Option (d).
Answer: Option B. -> 240
:
B
3:5 ⇒3x and 5x
Now, it’s given that
(3x+20)5x+20=1321
Cross multiplying; 63x + 420 = 65x + 260 So, x= 80
The markswill therefore be: Anju: 3x=3×80=240and Binoy: 5x=5×80=400.
:
B
3:5 ⇒3x and 5x
Now, it’s given that
(3x+20)5x+20=1321
Cross multiplying; 63x + 420 = 65x + 260 So, x= 80
The markswill therefore be: Anju: 3x=3×80=240and Binoy: 5x=5×80=400.
Question 67. Picnic invites two kinds of charges: bus fare, which is independent of the number of people attending the picnic and buffet lunch, which increases directly with an increase in the number of people. The charges are calculated to be Rs. 165 per head when there are 200 invitees and Rs. 170 per head when there are 150 invitees. What would be the charges per head when there are 100 invitees?
Answer: Option B. -> Rs.180
:
B
Ans. (b) Let the bus fare = Rs. x
and buffet lunch per head = Rs. y
x+200y=165×200.......(i)
x+150y=170×150.......(ii)
Then, x+100y=2×(ii)−(i)=51000−33000=18000
Therefore, Cost per head = Rs. 180
:
B
Ans. (b) Let the bus fare = Rs. x
and buffet lunch per head = Rs. y
x+200y=165×200.......(i)
x+150y=170×150.......(ii)
Then, x+100y=2×(ii)−(i)=51000−33000=18000
Therefore, Cost per head = Rs. 180
Answer: Option C. -> 2
:
C
Lets assume that the maximum marks are 100. total marks available =500
Total marksobtained by all 5 together =35×500=300
Which is divided in the ratio 3:4:5:6:7
Marks are 36, 48,60, 72 and 84. only 2 students get more than 70%.
:
C
Lets assume that the maximum marks are 100. total marks available =500
Total marksobtained by all 5 together =35×500=300
Which is divided in the ratio 3:4:5:6:7
Marks are 36, 48,60, 72 and 84. only 2 students get more than 70%.
Answer: Option B. -> 200
:
B
The total charge = Fixed component +Variable component
Z= F+kx
Where F and x are fixed
550 =F +k(4.5)
300=F + k(2)
Solving simultaneously, F= 100 and k= 100
Charges for 1 hour = 100 +1(100) =200
:
B
The total charge = Fixed component +Variable component
Z= F+kx
Where F and x are fixed
550 =F +k(4.5)
300=F + k(2)
Solving simultaneously, F= 100 and k= 100
Charges for 1 hour = 100 +1(100) =200
Question 70. A, B and C went for lunch to a restaurant. A had 100withhim,Bhad60 and C had 409.Theygotabillfor104 and decided to give a tip of $16. They further decided to share the total expenses in the ratio of the amounts of money each carried. The amount of money, which C paid more than what A paid, is
Answer: Option C. -> 65.25
:
C
They divided the bill in the ratio of money they carried.
So, 120 got divided A= 21, B= 12.65, C= 86.25. C paid 65.25 more than A.Option (3).
:
C
They divided the bill in the ratio of money they carried.
So, 120 got divided A= 21, B= 12.65, C= 86.25. C paid 65.25 more than A.Option (3).