Basic Arithmetic(Exams > Cat > Quantitaitve Aptitude ) Questions and answers for exam Preparation

Exams > Cat > Quantitaitve Aptitude

BASIC ARITHMETIC MCQs

Total Questions : 150 | Page 6 of 15 pages

Question 51. 6 children and 2 men complete a job in 6 days. Each child takes twice as much time a man takes to complete the same amount of job. In how many days will 4 men complete the same job.

Discuss Question

Answer: Option E. -> 7.5
:
E
Given that, 1 man = 2 child.
So, 6 children + 2 men = 3 men + 2 men = 5 men.So, 5 men complete a job in 6 days.
So, amount of work mandays

= 5 \times 6 = 30

man days. Now, when 4 men are working, then number of days taken

= \frac{30}{4} = 7.5

days
Hence option (d)

Question 52. (x-2) men can do a job in x days and (x+7) men can do a job in

{\frac{3}{4}}^{t h}

of the same work in (x-10) days. The no. of days in which (x+4) men can finish the job is___

Discuss Question

:
Total work is constant.

∴

Total work = (x-2)(x) =

\frac{4}{3}

*(x+7)(x-10)

\Rightarrow x^{2} - 6 x - 280 = 0

Solving for x; we get x = 20.
Now 18 men takes 20 days to complete work

∴

24 men will take

\frac{20 \times 18}{24}

days = 15 days
Alternatively:

(x - 2)

\to x

days

(x + 7)

\to (x - 10)

days for

{\frac{3}{4}}^{t h}

of work

\Rightarrow (x - 2)

will take

\frac{3}{4} x

days for

{\frac{3}{4}}^{t h}

of work
So

\frac{x - 2}{x + 7} = \frac{x - 10}{3 x / 4}

\Rightarrow x^{2} - 6 x - 280 = 0

So, x = 20
Now 18 men takes 20 days to complete work

∴

24 men will take

\frac{20 \times 18}{24}

days = 15 days

Question 53. A trader makes a profit equal to the selling price of 50 articles when he sold 80 of the articles. What

%

profit did he make in the transaction?

183%
176%
183.33%
166.67%
6500

Discuss Question

Answer: Option D. -> 166.67%
:
D
Soln:Let S be the selling price of 1 article.Therefore, the selling price of 80 articles = 80 S
The profit earned by selling these 80 articles = selling price of 50 articles = 50 S
We know that Selling Price (S.P.) = Cost Price (C.P) + Profit ofSelling price of 80 articles = 80 S and Profit = 50 S
80 S = C.P + 50 S. Hence, C.P = 80 S - 50 S = 30 S.Profit

% = (\frac{50 S}{30 S}) \times 100 = 166.67 %

Question 54. Alok borrows some money from the bank and the SI on the sum is

{\frac{1}{9}}^{t h}

the principal amount and the number of years is the rate of interest. Find r?

5.55%
2.33%
3.33%
None of these
Rs. 221970

Discuss Question

Answer: Option C. -> 3.33%
:
C
Answer = Option c
Principal = P
Time = x
Rate = x

S I = \frac{P}{9}

S I = \frac{P R T}{100} \frac{P}{9} = \frac{P x^{2}}{100}

x^{2} = \frac{100}{9} \Rightarrow x = \frac{10}{3} = 3.33 %

Question 55. A nano car is bought in 2012 for Rs.17576, if it’s value appreciates annually by

4 %

, what was its value three years ago?

13456
15625
14565
none of these
Rs. 221970

Discuss Question

Answer: Option B. -> 15625
:
B
Price three years ago

X \times (\frac{104}{100})^{3}

= present price
Price 3 years ago = X =

\frac{17576}{(1.04)^{3}}

Price 3 years ago= X =

\frac{17576 \times 25 \times 25 \times 25}{26 \times 26 \times 26}

= Rs15625 . Option (2).

Question 56. Ravi bought a bike with a marked price of Rs.40,000. The dealer gave him two successive discounts of

10 %

and

20 %

. After he bought the bike, he spent

10 %

of the cost of the bike on the accessories. At what price should he sell the bike to earn a profit of

10 % .

Rs. 27000
Rs. 38016
Rs. 37680
Rs. 34848
Rs. 35680

Discuss Question

Answer: Option D. -> Rs. 34848
:
D
Cost of the bike =

0.9 \times 0.8 \times 40000

= Rs. 28800
For Ravi total cost

= 28800 + (28800 \times 0.1) = 31680

So, for a profit of

10 %

he should sell the bike at

31680 + (0.1 \times 31680) = R s .34848

Hence option (d)

Question 57. The length of a rectangle is increased by

a = 30 %

and breadth is decreased by

b = 25 %

. What is the percentage change in the area of the rectangle?

2.5% increase
2.5% decrease
5% increase
None of these

Discuss Question

Answer: Option B. -> 2.5% decrease
:
B
Answer = option b
Initial area

= l \times b

Final area

= 1.3 l \times 0.75 b

= 0.975 l \times b

%

change

= (1 - 0.975) \times 100 = 2.5 %

decrease

Question 58. A bank gives out Rs.6000 to Customer A for 2 years and Rs.1500 to customer B for 4 years. It receives interest of Rs.900 from them put together. Find the rate of interest (SI)?

5%
10%
7.5%
12.5%
Rs. 221970

Discuss Question

Answer: Option A. -> 5%
:
A
Rs.6000 for 2 years Rs.12000 for 1 year and Rs.1500 for 4 years Rs.6000 for 1 year
Total Principal = Rs 18000 for 1 year

S I = \frac{P R T}{100} \to R a t e = \frac{900 \times 100}{18000} = 5 %

Question 59. In a village which has a barter system, 1 kg of rice is equivalent to 1 dozen bananas. Anil gives 1.5 kg rice to Binod using a false weight of 800 gm as 1 kg and takes 15 bananas. Who is in profit and what is the percentage profit?

Anil, 4.17%
Binod, 4.17%
Anil, 8.34%
Binod, 8.34%
None of these

Discuss Question

Answer: Option A. -> Anil, 4.17%
:
A
Soln:
800 gm ==1 kg ,1.5 kg == 1.2 kg
Anil actually sold 1.2 kg rice and so he should get

1.2 \times 12 = 14.4

bananas but he got 15 bananas. So, Anil is making a profit of 0.6 which is

4.17 % .

Hence option (a).

Question 60. Two alloys containing copper and zinc are in the ratios 5:8 and 5:3.If they are melted in equal quantities, The ratio of Zinc to copper in the resultant alloy is?

105:103
114:120
123:154
103:105

Discuss Question

Answer: Option D. -> 103:105
:
D