Basic Arithmetic(Exams > Cat > Quantitaitve Aptitude ) Questions and answers for exam Preparation

Exams > Cat > Quantitaitve Aptitude

BASIC ARITHMETIC MCQs

Total Questions : 150 | Page 14 of 15 pages

Ravi bought a bike with a marked price of Rs.40,000. The dealer gave him two successive discounts of $10 %$ and $20 %$ . After he bought the bike, he spent
$10 %$ of the cost of the bike on the accessories. At what price should he sell the bike to earn a profit of $10 % .$

Rs. 27000
Rs. 38016
Rs. 37680
Rs. 34848
Rs. 35680

Discuss Question

Answer: Option D. -> Rs. 34848
:
D

Cost of the bike = $0.9 \times 0.8 \times 40000$ = Rs. 28800

For Ravi total cost $= 28800 + (28800 \times 0.1) = 31680$

So, for a profit of $10 %$ he should sell the bike at $31680 + (0.1 \times 31680) = R s .34848$

Hence option (d)

Question 132.

Two cars are of the same cost price. One is sold at a profit of $15 %$ and the other for Rs. 23000 more than the first. If the net profit is $20 %$ , find the cost price of each car.

Rs. 280000
Rs. 230000
Rs. 282000
Rs. 327500
Rs. 221970

Discuss Question

Answer: Option B. -> Rs. 230000
:
B

Let the cost price be ‘p’ then

2 (1.15 P) + 23000 = 2 (1.2 P)

0.1 P = 23000

P = Rs.230000

Hence option (b)

Question 133.

A bank gives out Rs.6000 to Customer A for 2 years and Rs.1500 to customer B for 4 years. It receives interest of Rs.900 from them put together. Find the rate of interest (SI)?

$5 %$
$10 %$
$7.5 %$
$12.5 %$
Rs. 221970

Discuss Question

Answer: Option A. ->

5 %

:
A

Rs.6000 for 2 years Rs.12000 for 1 year and Rs.1500 for 4 years Rs.6000 for 1 year

Total Principal = Rs 18000 for 1 year

$S I = \frac{P R T}{100} \to R a t e = \frac{900 \times 100}{18000} = 5 %$

Question 134.

Alok borrows some money from the bank and the SI on the sum is ${\frac{1}{9}}^{t h}$ the principal amount and the number of years is the rate of interest. Find r?

$5.55 %$
$2.33 %$
$3.33 %$
None of these
Rs. 221970

Discuss Question

Answer: Option C. ->

3.33 %

:
C

Answer = Option c

Principal = P

Time = x

Rate = x

$S I = \frac{P}{9}$

$S I = \frac{P R T}{100} \frac{P}{9} = \frac{P x^{2}}{100}$

$x^{2} = \frac{100}{9} \Rightarrow x = \frac{10}{3} = 3.33 %$

Question 135.

A nano car is bought in 2012 for Rs.17576, if it’s value appreciates annually by $4 %$ , what was its value three years ago?

13456
15625
14565
none of these
Rs. 221970

Discuss Question

Answer: Option B. -> 15625
:
B

Price three years ago $X \times (\frac{104}{100})^{3}$ = present price

Price 3 years ago = X = $\frac{17576}{(1.04)^{3}}$

Price 3 years ago= X = $\frac{17576 \times 25 \times 25 \times 25}{26 \times 26 \times 26}$ = Rs15625 . Option (2).

Question 136.

Which is the least number, which when subtracted from both the numerator and the denominator of the ratio $\frac{80}{70}$ , gives $\frac{13}{11}$ ?

Discuss Question

Answer: Option C. -> 15
:
C

Solving conventionally,

Let x be the required number

$\frac{80 - x}{70 - x} = \frac{13}{11}$

880 – 11x = 910 – 13x

2x = 30

x= 15

Shortcut:- Use answer options. Always start with the middle answer option

Question 137.

There are 5 friends in a class who get marks in the ratio 3:4:5:6:7. The maximum marks are the same in each case. The total marks obtained by the 5 are ${\frac{3}{5}}^{t h}$ the maximum obtainable marks. How many friends got more than $70 %$ of the total marks?

0
1
2
more than 2

Discuss Question

Answer: Option C. -> 2
:
C

Lets assume that the maximum marks are 100. total marks available =500

Total marks obtained by all 5 together $= \frac{3}{5} \times 500 = 300$

Which is divided in the ratio 3:4:5:6:7

Marks are 36, 48,60, 72 and 84. only 2 students get more than $70 % .$

Question 138.

There is a bag with a mixture of sugar, rice and wheat grains. The quantity of rice is ${\frac{4}{5}}^{t h}$ that of wheat and the quantity of sugar is ${\frac{3}{4}}^{t h}$ that of rice. In 12 kg of the mixture how much wheat and sugar will be there?