Basic Arithmetic(Exams > Cat > Quantitaitve Aptitude ) Questions and answers for exam Preparation

Exams > Cat > Quantitaitve Aptitude

BASIC ARITHMETIC MCQs

Total Questions : 150 | Page 2 of 15 pages

Question 11. Ajit can do a certain work in 24 days. Bharath can do the same work in 30 days. When Chandra joins them and they do the work together, they complete the work in 12 days. Find out the time required by Chandra to complete the work alone

100 days
125 days
130 days
120 days

Discuss Question

Answer: Option D. -> 120 days
:
D
In one day Ajit can do

(\frac{100}{24}) %

of the work.
In one day Bharath can do

(\frac{100}{30}) %

of the work.
Working together they can do

(\frac{100}{24}) % + (\frac{100}{30}) % = 7.5 %

of the work in one day.
Now when Chandra joins them, they complete the work in 12 days Ajit, Bharath and Chandra together complete

(\frac{100}{12}) %

of the work in a day.
Now, Ajit and Bharath do

7.5 %

of the work in a day.
Ajit, Bharath and Chandra do

(\frac{100}{12}) %

of the work in a day.
Chandra can do

(\frac{100}{12} - 7.5) % = (\frac{10}{12}) %

of the work in a day.
So, to complete

100 %

of the work, Chandra will take

[\frac{100}{(\frac{10}{12})}]

= 120 days. Hence option (e).
2nd method:- In 12 days ajit completes

\frac{12}{24}

i.e

50 %

and Bharat completes

\frac{12}{30}

i.e

40 %

, then chandra completes

(100 - 90) = 10 %

work in 12 days. Then he will take 120 days to complete full work.

Question 12. A milk container contains

5 %

milk

&

rest water while another contains

50 %

milk & rest water. What amount of mixture should be taken from both the containers if we require 26 litres mixture with ratio of milk

&

water as 3: 2?

2, 24
1, 25
8, 18
4, 22
7.5

Discuss Question

Answer: Option D. -> 4, 22
:
D
Quantity of milk in the first container =

\frac{1}{20}

Quantity of milk in the second container =

\frac{1}{2}

Applying Alligation:

A Milk Container Contains 5% milk & Rest Water Whi...

So, mixture should be taken out from the containers in the ratio = 2: 11
Total amount of mixture required = 26 litres. So, quantity required from

1^{s t}

container = 4 litres and from the second container = 22 litres.
Hence option (d)

Question 13. Two cars are of the same cost price. One is sold at a profit of

15 %

and the other for Rs. 23000 more than the first. If the net profit is

20 %

, find the cost price of each car.

Rs. 280000
Rs. 230000
Rs. 282000
Rs. 327500
Rs. 221970

Discuss Question

Answer: Option B. -> Rs. 230000
:
B
Let the cost price be ‘p’ then
2 (1.15 P) + 23000 = 2 (1.2 P)
0.1 P= 23000
P= Rs.230000
Hence option (b)

Question 14. At a new book-store, the inaugural discount is as follows. If the value of purchase

<

3200, the buyer gets a

14 %

discount. If the purchase

3200 < x < 6300

, then the buyer gets a

16 %

discount. Above 6300, the discount percentage is x. A certain buyer gets a total discount of Rs. 1520 which is

16 %

of the purchase value. What is x?

Discuss Question

Answer: Option C. -> 18%
:
C

16 %

of purchase value = Rs. 1520
purchase value = 9500

1520 = 14 % o f 3200 + 16 % o f 3100 + x % o f 3200

1520 = 944 + x % o f 3200

576 = x % o f 3200

x = 18 %

Question 15. Ram adjusted his electronic weighing scale in a typical way. But he gives a discount of

10 %

in every transaction. His weighting scale shows 5 kg for 4 kg. What is the actual profit

%

when the displayed weight is 10 kg, if he sells the commodity at its cost price?

12.5%
10%
5%
25%
40%

Discuss Question

Answer: Option A. -> 12.5%
:
A
5kg ---> 4kg
10kg ---> 8kg
C.P of product of 1 kg = x
Total C.P = 8x
S. P = 10x - x(10% discount of 10x)
= 9x
Profit % =

\frac{x}{8 x} \times 100

= 12.5%

Question 16. There is a bag with a mixture of sugar, rice and wheat grains. The quantity of rice is

{\frac{4}{5}}^{t h}

that of wheat and the quantity of sugar is

{\frac{3}{4}}^{t h}

that of rice. In 12 kg of the mixture how much wheat and sugar will be there?

7 kg
10 kg
8 kg
none of these

Discuss Question

Answer: Option C. -> 8 kg
:
C
Answer = Option c
If we take the amount of Sugar as 3x, then Rice = 4x and Wheat = 5x (ratio = 3:4:5; as rice=

\frac{4}{5}

wheat and sugar =

\frac{3}{4}

rice)
12x= 12 x=1
Wheat = 5 kg and Sugar = 3 kg. Total = 8 kg

Question 17. P,Q,R invested Rs 1000, Rs 600 and Rs 400 respectively to start a business. The profit is Rs 200 which is to be divided among P,Q,R in the ratio of their capital invested. What share does R get?

Discuss Question

Answer: Option C. -> 40
:
C
R’s share of Profit

= \frac{2}{10} \times 200 = R s .40

Question 18. One year payment to the servant is Rs. 200 plus one shirt. The servant leaves after 9 months and receives Rs.120 and a shirt. Then find the price of the shirt.

Rs. 80
Rs. 100
Rs. 120
Cannot be determined

Discuss Question

Answer: Option C. -> Rs. 120
:
C
Solution:At the first glance it seems that the answer is cannot be determined but let’s investigate further. Let the price of the shirt be 12X, where every month he earns

{\frac{1}{12}}^{t h}

of the shirt price plus his wages.He earns

\frac{200}{12}

every month as salary .. So in 9 months he should've earned 150 cash. But he only got 120 hence Rs.30 went to his shirt deduction.Therefore 3X= 30

&

12X= 120. Option (c).

Question 19. The average of temperatures at noontime from Tuesday to Saturday is 50; the lowest one is 45, what can be the possible maximum range of the temperatures.

Discuss Question

Answer: Option B. -> 25
:
B
The average of the 5 temperatures is:

\frac{a + b + c + d + e}{5} = 50

One of these temps is 45:

\frac{a + b + c + d + 45}{5} = 50

.
Solving for the variables: a + b + c + d = 205
In order to find the greatest range of temps, we minimize all temps but one. Remember, though, that 45 is the lowest temp possible, so: 45 + 45 + 45 + d = 205 Solving for the variable: d = 70
70 - 45 = 25 Option (b).
2nd method:-For finding maximum range, we will take 4 days minimum out of 5 days i.e 4 days temp. will take 45, then total negative deviations will be 20. Thus for average 50, positive deviation should be also 20 . Thus highest temp will be (50+20)=70 degrees. Then range =70-45 = 25. Option (b).

Question 20. An Aspirant scored 98 in his 19th Mock CSAT and thus increases his average by 4. What is his average after the 19th Mock CSAT.