An Aspirant scored 98 in his 19th Mock CSAT and thus increases his average by 4.

Question

An Aspirant scored 98 in his 19th Mock CSAT and thus increases his average by 4. What is his average after the 19th Mock CSAT.

Options:

A . 22

B . 24

C . 26

D . Cannot be determined

Answer: Option C
:
C
Let the average score after

18^{t h}

Mock CSAT be x.

1^{s t}

Method:- Weighted Average:

\frac{18 x + 98}{19} = x + 4; x = 22

answer is

x + 4 = 26

, option (c).

2^{n d}

Method:- Using Alligation

Use the reverse gear approach now.
Put X = 22; we will get 18: 1; answer is x + 4 = 26, option (c).

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