Diameter of a circular fountain= 14 m, so radius = 7 m.

Let the length of the square be 'a'.

 Total cost = cost of fountain + cost of grass.

Hence, ₹ 6460 = (area of fountain x cost per $m^2$) + (area of square park -area of circular fountain) x (cost for grass per $m^2$)

6460 = ($\pi (7{)}^2\times 10)+((a^2-\pi (7{)}^2\times 20)$

6460 = $(154\times 10)+(a^2-154)\times 20$

6460 =1540+($a^2-154)\times 20$ 

a = 20 m.

Area of the path = Area of the outer rectangle - Area of the inner rectangle

The path so formed is effectively adding 1.5m + 1.5m = 3m to the length and breadth of the park, as shown in the figure.

So, area of the path = 21 $\times$ 18 - 18 $\times$ 15 = 18 $\times$ (21 - 15) = 18 $\times$ 6 = 108 $c{m}^2$

The hectare (symbol ha) is an SI accepted metric system unit of area equal a square with 100-metre sides (10,000 $m^2$) and primarily used in the measurement of land.
Hence, 1 hectare = 10000$m^2$.

To find the perimeter in centimeters, we have to convert all the dimensions into centimeters.

$1500mm=\frac{1500}{10}cm=150cm$

$2m=2\times 100cm=200cm$

$500mm=\frac{500}{10}cm=50cm$

$1m=1\times 100cm=100cm$. So, after converting all the dimensions to centimeters, the lengths of the sides of polygon are as follows:

Perimeter of the polygon (in cm) = (100 + 150 + 50 + 200 + 50 + 100) cm = 650 cm

The area of a square is given by squaring its edge length. So the area of the given square is $a^2$.

Given that the area of the blue cloth = $\frac{1}{10}ofareaofyellowcloth$
$\Rightarrow \frac{1}{10}of60c{m}^2=6c{m}^2$
Since area of the total cloth = Area of the yellow cloth + Area of the blue cloth + Area of the red cloth required,
$\Rightarrow$Area of the red cloth required = Area of the total cloth - Area of the yellow cloth -  Area of the blue cloth
$\Rightarrow 80c{m}^2-60c{m}^2-6c{m}^2$=$14c{m}^2$

Thus, area of the red cloth = $14c{m}^2$

The area of a quarter circle is one-fourth of that of the complete circle because the area is the region enclosed. For a semi-circle, it is half of the total area and for quarter circle, it is one-fourth. So, area of a quarter circle with radius $r=\frac{\pi r^2}{4}$

The circumference is the length of the boundary. For a quarter circle with radius r, circumference is given by  $\left(\frac{\pi r}{2}\right)+2r$.

So, statement 1 is true and statement 2 is false.

$\text{Area of a parallelogram}=base\times height\text{Area of kajubarfi (parallelogram)}=(4\times 3)c{m}^2=12c{m}^2$