Question
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Raj runs and covers a distance of 0.616 km in the ground which is in the shape of semi-circle mounted on the rectangle as shown below. Find the number of rounds taken by Raj to cover the distance
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Answer: Option A
:
Perimeter of half circle = π r + d .
But according to the figure given here ,
the perimeter of the part of the semi circle = π×142=7π=7× 227 =22 m. (Radius is half the diameter)
Hence, total perimeter = Perimeter of the half circle + side of 14 m + side of 10 m + side of 10 m
= (22 + 14 + 10 +10) m = 56 m.
Number of rounds he will have to make to complete the punishment = 0.616 × 1000 m56 m = 11 rounds.
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:
Perimeter of half circle = π r + d .
But according to the figure given here ,
the perimeter of the part of the semi circle = π×142=7π=7× 227 =22 m. (Radius is half the diameter)
Hence, total perimeter = Perimeter of the half circle + side of 14 m + side of 10 m + side of 10 m
= (22 + 14 + 10 +10) m = 56 m.
Number of rounds he will have to make to complete the punishment = 0.616 × 1000 m56 m = 11 rounds.
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