7th Grade > Mathematics
AREA AND PERIMETER MCQs
Perimeter And Area
Total Questions : 99
| Page 2 of 10 pages
Answer: Option B. -> 72 m2
:
B
Let ABCD be the square park and the region shaded in green be the path.
Here, side length of the outer square, AB = 11 m (given)
and the path is 2 m wide.
⇒ Side length of the inner square, HG
= 11 - 2 - 2 = 7 m
We know that area of a square = side2
⇒ Area of the path = Area of the outer square - Area of the inner square
=112−72=121−49=72m2
:
B
Let ABCD be the square park and the region shaded in green be the path.
Here, side length of the outer square, AB = 11 m (given)
and the path is 2 m wide.
⇒ Side length of the inner square, HG
= 11 - 2 - 2 = 7 m
We know that area of a square = side2
⇒ Area of the path = Area of the outer square - Area of the inner square
=112−72=121−49=72m2
Answer: Option C. -> 169 cm2
:
C
Area of the square = Side × Side
Given: Side = 13 cm
∴ Area = 13 × 13 = 169 cm2
:
C
Area of the square = Side × Side
Given: Side = 13 cm
∴ Area = 13 × 13 = 169 cm2
Answer: Option B. -> 1 cm2
:
B
In the given figure, we have length = 4 cm and breadth =14 cm
Area of the figure = length× breadth
⇒ Area of the given rectangle= 4 cm × 14 cm = 1cm2
:
B
In the given figure, we have length = 4 cm and breadth =14 cm
Area of the figure = length× breadth
⇒ Area of the given rectangle= 4 cm × 14 cm = 1cm2
Answer: Option B. -> 9000 cm2
:
B
1 m = 100 cm.
Hence 1 sq. m =100×100cm2
⇒0.9m2=0.9×100×100=9000cm2( shifting the decimal by 1 place)
:
B
1 m = 100 cm.
Hence 1 sq. m =100×100cm2
⇒0.9m2=0.9×100×100=9000cm2( shifting the decimal by 1 place)
Answer: Option B. -> 200 cm2
:
B
Given: The length of the sides of each square is 10 cm.
For the rectangle formed:
Length= 10 cm + 10 cm = 20 cm
Breadth = 10 cm
Area of therectangle = Length × Breadth = 20cm×10cm=200cm2
:
B
Given: The length of the sides of each square is 10 cm.
For the rectangle formed:
Length= 10 cm + 10 cm = 20 cm
Breadth = 10 cm
Area of therectangle = Length × Breadth = 20cm×10cm=200cm2
Answer: Option D. -> 90 m2
:
D
Area of the given shape = area of the two rectangles
= (10m×5m)+(5m×8m)
= 50m2+40m2
=90m2
:
D
Area of the given shape = area of the two rectangles
= (10m×5m)+(5m×8m)
= 50m2+40m2
=90m2
Answer: Option D. -> 4 cm
:
D
Given : Perimeter of the given figure= 15 cm
Let the length of the third side be x.
Perimeter of a figure = Sum of lengths of itssides = AB + BC + AC
⇒ 15 cm = 6 cm + 5 cm + x
⇒ 15 cm = 11 cm + x
⇒x = 15 cm - 11 cm
⇒x = 4 cm
Therefore, the third side is 4 cm long.
:
D
Given : Perimeter of the given figure= 15 cm
Let the length of the third side be x.
Perimeter of a figure = Sum of lengths of itssides = AB + BC + AC
⇒ 15 cm = 6 cm + 5 cm + x
⇒ 15 cm = 11 cm + x
⇒x = 15 cm - 11 cm
⇒x = 4 cm
Therefore, the third side is 4 cm long.
Answer: Option A. -> Be more than the square
:
A
It will be more than the perimeter of square because in the case of square, we consider 4 sides but in the case of triangle, we have 6 sides to consider since each triangle has 3 sides.
:
A
It will be more than the perimeter of square because in the case of square, we consider 4 sides but in the case of triangle, we have 6 sides to consider since each triangle has 3 sides.