7th Grade > Mathematics
AREA AND PERIMETER MCQs
Perimeter And Area
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Formula: 1 Mark
Answer: 1 Mark
Given that,
The perimeter of a rectangular field is 50 m.
The length of the field is 13 m.
Perimeter of rectangular field = 2( length + breadth)
Or, Breadth=perimeter2−length
Or, Breadth = 25 - 13 = 12 m
Area of rectangle = length × breadth =13×12 = 156 sq. m
The area of the rectangular field is 156 m2.
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Formula: 1 Mark
Answer: 1 Mark
Area of the circle of radius R is π×R2
Radius of the given circle = 10 m
Area of the given circle = π×102
= 314 m2
The area of the circle is 314 m2.
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Formula: 1 Mark
Answer: 1 Mark
Given that,
The side of a parallelogram is 3 m and the corresponding altitude = 38m
Let the side and altitude of the parallelogram be A and B
Area of the parallelogram = A×B
Given side and altitude are 3 m and 38m
Area of the given parallelogram
=(3)×38=1.125m2
The area of the parallelogram is 1.125m2.
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Formula: 1 Mark
Answer: 1 Mark
Given that,
Area of a parallelogram is 24 cm2
Area of parallelogram = Base × height
Or, Height = AreaBase
On substituting the values, we get
Height = 244 = 6 m
So, the height of the parallelogram is 6 m.
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Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Let the radius of the pizza be r1 and radius of the cake be r2.
Given: area of the pizzaarea of the cake=14
Now, area of a circle = πr2
⇒πr12πr22=14
⇒r21r22=12
⇒r1r2=12
Therefore, the ratio of their radii is 12
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Formula : 1 Mark
Process : 1 Mark
Result : 1 Mark
Height = 5cm
Given base is divided into two equal parts, so base length = 3+3 = 6cm
Area of the triangle = 12×base×height
= 12×5100×6100
= 1510000
= 0.0015
= 0.0015 m2
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Formula: 1 Mark
Radius: 1 Mark
Area: 1 Mark
Given that,
The entire length of the boundary is 628 m.
The perimeter of a cricket of radius r meters is 2×π×r meters
Given perimeter of the ground = 628 m
r = 628÷(2×π) =100 m
The distance of the boundary from the centre of the pitch is 100 m.
The area of a circle is π×(r)2
Area of the ground = π×(100)2
= 31400 m2
The area of the ground is 31400 m2.
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Formula: 1 Mark
Steps: 2 Marks
Result: 1 Mark
Length of the stick is equal to the perimeter of circle and square individually.
Circle of given radius has a perimeter of 628 m.
Side of square = 157 m
Radius of the given circle:
= 6282×π
= 100m
Area of the circle:
= π × r2
= π × 1002
= 3.14× 1002
= 31400m2
Area of the square
= length×length
= 157×157
= 24649m2
The area of circle is greater than area of square.
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Formula: 1 Mark
Steps: 1 Mark
Application: 1 Mark
Answer: 1 Marks
Given that,
The side of the square ABCD = 10 m.
Now the diameter of the circle will be equal to the side of the square ABCD = 10 m.
Area of the square = a2
Area of the square is (10) × (10) = 100 m2
Given diameter of circle = 10 m
Radius of the circle = 102 = 5 m
Area of the circle
= π × (r2)
= π × (52)
= 78.5m2
Area of the triangle BDE
= 12 × (BD) × (DE)
= 0.5 × (10) × (10)
= 50 m2
Area of the shaded region
= Area of square ABCD - Area of circle + Area of triangle BDE
= 71.5 m2
So, the area of the shaded region is 71.5 m2.
A man is walking in a circular park. In one round he completes 314 m. If there is a man at the opposite end of the diameter which is drawn from the point where the man is standing. Find the minimum distance he has to walk to meet his friend who is sitting at the described point? Also, find the area of the circular park. Take π=3.14 [3 MARKS]
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Steps: 1 Mark
Shortest Distance: 1 Mark
Area: 1 Mark
If the man has to cover the minimum distance, he has to walk along the diameter.
Circumference of the circle = 314 m
Radius of the given circle = 3142π
= 50 m
Diameter = (2)×(50) = 100 m
The radius of the circular park = 1002 = 50 m
The area of the circular park = π×r2
On substituting the values, we get
Area = π×502 = 7850m2